The R2 and R3 is in parallel combination. So the equivalent resistance will be= (8×8)/16 = 4
Applying Kirchoff's law in the circuit:
-Vc -Vb - 4i + Va - 2i =0
=> -20 -15- 4i+ 25-2i = 0
=> 6i = -10
=> i = -(10/6) Amp
The current in the circuit will be (10/6) Amp.
The voltage across the R3 resistance = (10/6)×(4)=(40/6)V
The power dissipation by R3 = (40/6)²/8 = 5.55 W
Please comment if you have any doubt and like if it helps.
Happy learning.
The circuit shown in the figure below contains three resistors (R1, R2, and R3) and three...
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