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Problem 3 (30 points). Given an analog signal x(t) = 6 cos(200xt)+3 cos(600xt) + COS(1600xt) a. What is the minimum sampling
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Given 2(t) = 6 cos ( 200114 )+ 3Cos (6001t)+cos (1600114) (a) fir 100 Hz f2e 300 HZ f3 - 800 HZ Minimum fs Nyquist facequency

6) + like (f-100) 48 (+100)] + [86-300) +86-1300)] #8 (f-600) +56F+800)] Then x(f-n) is a impulse train of x (t) Seperated by

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