Question

Solve the triangle B = 73° 15', c=31 m, a = 75 m What is the length of side b? b=m (Round to the nearest whole number as needed.) What is the measure of angle A? A= (Round to the nearest whole number as needed.) What is the measure of angle C? C=DºD' (Round to the nearest whole number as needed.)

Answer 1

Given C=31m Q 75m 73º. 15" B = 73:25° + > Cosine law To find Side b. using b=1a²c2-aac Cos B 775)+(31) +-2475)(31Cost73-25) b = 72. 43 m To find Angle A. use sine Rule a SinA Sin B b Sing » Sina X Q Sin(73.25) **5 b 72.43 Sint 0.95757 *75 72.43 15) A = Sint 10.9915) § 2.54 in degrees 0 A= е A = 8232' in degrees i minutes To find Angle A+B+C : 180 C= 180- 73.25 - 82.54 i' C-214.20 c=24° 12

Hence, side b= 72.43 m. Angle A = 82° 32' 2 Angle 24°10'