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Solve the triangle with the given parts. A=99.6°, b=8, c=13 What is the length of side a? (Round to four decimal places.) Wha
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Answer #1

A=99.6, 68, C=13 Cosine Rule: qa_ b 2 + ca- abccor A QP (8)2+(13)2- -8-13 C08 (99-6) 264+169 - 208X -0.166768747 = 233 +34.68

answered by: ANURANJAN SARSAM
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Answer #2

A=99.6, 68, C=13 Cosine Rule: qa_ b 2 + ca- abccor A QP (8)2+(13)2- -8-13 C08 (99-6) 264+169 - 208X -0.166768747 = 233 +34.68aQ+62-22 ab (16-361a)*+ (8)2 –(13)2 2.(16-3612) -8 = 267.688865764-169 261.7792 cosca 0-621413612 cacos (0.621 4.73612) (= 51

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