We know, to find out , we have to substitute the function in place of the variable 'x' in the function .
That is
Hence, we got the simplified form
Let f(x) = 4x + 4 and g(x) = 522 + 5x. After simplifying, (fog)(x) =
Let f(x) = 4x + 5 and g(x) = 3x2 + 2x. After simplifying, (fog)(x) =
Let f(x)=5x^2+9 and g(x)=x-4 A) Find the composite function (fog)(x) and simplify. B) Find (fog) (3)
Given that f(x) = 4x + 3 and g(x)=x*, find (fog)(-4). (fog)(-4)=
4 - Let f(x) = 4 – 5x and g(x) = 2 4 be functions from R into R. Prove that f and g are inverse functions by demonstrating that fog=iR and go f = ir.
Let f(x) = 3x + 2 and g(x) 3x + 2 and g(x) = 4x2 + 2x. After simplifying, (fog)(x) =
Q4 (4 points) (a) (1.5p) Find f +g-h, fog, fog•h if f(x) = (x - 3, g(x) = x^, and h(x) = x* + 2 (b) 0(1p) Find the inverse of the function f(x) = 4x - 1 2x + 3 () (0.5p) Find f(-)) (c) Simplify: 0 (1p) In(a) + { ln(b) + Inc mais)
What is the composition(fog)(x) when f(x) = 2x+6 and g(x)=x2-1, before simplifying? a.(fog)(x)=x2-1+2x+6 b.(fog)(x)=(2x+6)2-1 c.(fog)(x)=2(x2-1)+6 d.(fog)(x)=(2x+6)(x2-1)
Given that f(x) = x2 + 4x and g(x) = x + 7, calculate a)fog(z)= | # Preview syntax error g o f()- Preview (c) f o f(x)- [- # Preview (d) go g(x)- Preview
Use f(x) = 5x – 2 and g(x)= |x| to evaluate each expression. (a) (fog)(-3) (b) (g of)(6) (a) (fog)(-3)=1 (Simplify your answer.) (b) (gof)(6)= (Simplify your answer.)
4) Let f(x) = a) fog and its domain x -4 and g(x) = 13. Find each of the following: b) gof and its domain