Question

A driver starts his car with the door on the passenger's side wide open (0 = 0). The 100-b door has a centroldal radius of gyration k =12 in., and its mass center is located at a distance r = 20 in. from its vertical axis of rotation. Determine the smallest constant acceleration that the driver can maintain if the door is to close and latch, knowing that as the door hits the frame its angular velocity must be at least 1.75 radis for the latching mechanism to operate. If the door is to close and latch, the smallest constant acceleration that the driver can maintain is 2

Answer 1

Soin: Given that me 100lb n = 20 in. (ah/a)+ A of 1.75 rad read/ (AGIA) K = 12 in →AA Initially, o=0 considen Kinematic of lystem, Now, as Aaa (AGA) t = ra kinetics of lystem, considen the r A Μπα Ах m (aum) ма А G dal B Taking moment about point A; Σ ΜΑ : EC MA) eff Os man i cose ī at + (madla - manica coso ) mãza + mia = ад п K2+ as ceso Now, take a=co de do ( 20 A) an w dw coso CS Scanned with code scanng 12. au) + ( )?

بينه و بين 11 0.441 aA.coso do w dwa 0.441 an.colo do Wf 1/2 swdco I (0.441 an ) caso do woof 1 2 واحد 0.4410A "/ [ fino lo WF?: 0-882 QA Sin I -fino] 2 wf?. 0.882 2A 2 0.882 AA (1.75) Tam 3.4725 Ani. S2 CS Scanned with CamScanner