Question

The metal equilateral triangle in the figure, 20 cm on each side, is halfway into a 0.35 T magnetic field. (Figure 1) Part A What is the magnitude of the magnetic flux through the triangle? Express your answer with the appropriate units. μΑ ? $ = 0.000026 Wb Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining Part B If the magnetic field strength decreases, what is the direction of th Figure 1 of 1 clockwise X X XXI counterclockwise XXX Submit Previous Answers XX 20 cm XX Correct Here we learn how to use Lenz's law to determine the dire 609 Provide Feedback

Answer 1

Solution :

We have given :

The length of the sides of the triangle is : L = 20 cm = 0.20 m

And, Magnetic field strength : B = 0.35 T

.

Now, Area of equilateral triangle is given by :

$A=\frac{\sqrt{3}}{4}\cdot L^2$

Therefore, Area of the given equilateral triangle will be :

$A=\frac{\sqrt{3}}{4}\cdot (0.20\ m)^2=0.0173\ m^2$

.

Now, Magnetic flux is given by : Φ = B A

But, Here only half part of the triangle is inside the magnetic field.

Thus, Magnetic flux through the triangle will be :

$\Phi =B\left ( \frac{A}{2} \right )=(0.35\ T)\left ( \frac{0.0173\ m^2}{2} \right )=\mathbf{0.00303\ Wb}$

Thus, Magnetic flux through the triangle will be : Φ = 3.03 x 10^-3 Wb