Question

A Review Constants Periodic Table Part A Air flows through the tube shown in (Figure 1) at a rate of 1100 cm/s. Assume that air is an ideal fluid. The density of mercury is 13600 kg/m3 and the density of air is 1.20 kg/m3 What is the height h of mercury in the right side of the U-tube? Suppose that di = 2.4 cm and d2 = 5.0 mm Express your answer with the appropriate units. Figure < 1 of 1 HA ? h = Value Units d. Submit Request Answer h Provide Feedback Next > Ho P Pearson

Answer 1

h represents the pressure difference between 1 and 2. So we have to find the pressure difference between 1 and 2 which can be done by using bernoulli equation.

Please find the attached solution.

Prob. O= 1100 cm3/s fuq » 18600 kq his fair= 1.2kg /m3. di = 2.4cm = 0.024 m da = 5mm 58103 4.5238X104 m2 4.5238x lo UD دم nd, A, E 4 1-9635X 1075 m2 Az = I dz? = 4 in repion ! velocity AIU 1100 x 10-6 U, oke 4.5238 X 1024 Vi = 2.43 mis Velowkey in repron 2. lloox 10-6 و به وفا A 2 1.96x105 V = 56 mis

Bernoulli equation between 1+2. Pit Ighit & pene - Pst Eghet ļ pusa - his hz. Potential heads. Pi-P2 } ? ( 0,26,2) P-2 P - P2 x 1.20 (650)?- (2:43) P.-P2 = 1899.57 Pa And Pirpa Sug. goko 13600x 9.81x ho 1879.57 كه 0.01408 m h = 14.00 mm