Question

#6 Finding the Phase Angle in a Series RLC Circuit Suppose a RLC series cir- cuit driven with an AC voltage source has a resistance of 35.6 12, a capacitative reactance of 29.3 2, and an inductive reactance of 43.5 22. What is the impedance Z? A. Z= 19.6 S2 B. Z = 23.5 2 C. Z=31.4 12 D. Z=38.3 82 2. #7 Finding the Phase Angle in a Series RLC Circuit In #6. what is the phase angle o? O A. O = 0 OB. O = 21.2° O Co= 39.5 Do=173

If someone can answer question 7, I would greatly appreciate it.

Answer 1

6)

$R = 35.6 \Omega$

$X_{C} = 29.3 \Omega$

$X_{L} = 43.5 \Omega$

impedance $Z = \sqrt{R^{2}+\left ( X_{L}-X_{C} \right )^{2}}$

$Z = \sqrt{\left ( 35.6\Omega \right )^{2}+\left ( 43.5 \Omega -29.3 \Omega \right )^{2}}$

$Z = 38.3 \Omega$

Ans ===> D

7)

Phase angle is $Tan \Phi = \left ( \frac{X_{L}-X_{C}}{R} \right )$

$Tan \Phi = \left ( \frac{43.5 \Omega -29.3 \Omega }{35.6 \Omega } \right )$

$Tan \Phi =0.39887$

$\Phi =Tan^{-1}\left (0.39887 \right )$

$\Phi =21.7^{o}$

Ans ===> B