Question

QUESTION 9 Given X = 20, N2 = 6; X2 = 15, N2 = 5,534-22 = 2.5 a=0.05, 2 tail. Our conclusion would be: since 11. reject the nuit Once of 11 retain the null since of retain the nu O since df9. reject the null QUESTION 10

Answer 1

Since , the test is two-tailed test.

Now , df=degrees of freedom=N1+N2-2=6+5-2=9

The critical values are , $t_{df,\alpha/2}=t_{9,0.05/2}=\pm 2.262$

The decision rule is ,

Reject Ho , if t-stat>2.262 or t-stat<-2.262 , otherwise retain reject Ho

The test statistic is ,

$t_{stat}=\frac{\bar{X_1}-\bar{X_2}}{S_{\bar{X_1}-\bar{X_2}}}=\frac{20-15}{2.5}=2.00$

Decision : Here , t-stat=2.00<2.262

Therefore , retain the null hypothesis

Therefore ,

df=9 , retain the null