Calculate ΔG°R for: (using: ΔG°R = ΔH°R - T ΔS°R ) (Standard T and please show all work!)
2KClO3 (s) --> 2KCl (s) + 3O2 (g)
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Calculate ΔG°R for: (using: ΔG°R = ΔH°R - T ΔS°R ) (Standard T and please show...
For the values give for ΔH and ΔS, calculate ΔG foreach for each of the following reactions at 298 K. If the reactionis not spontaneous under standard conditions at 298 K, at whattemperature (if any) would the reaction become spontaneous? a) 2PbS(s)+3O2(g) ---> 2PbO(s)+2SO2(g) ΔH= -844kj ; ΔS = -165 J/K b)2POCl3(g)--->2PCl3(g)+O2(g) ΔH= 572kJ ; ΔS= 179 J/K
Determine ΔG◦rxn using the following information. 2H2S(g)+3O2(g) ---> 2H2O(l)+2SO2(g) ΔH= +1.12kJ ;ΔS= -390.7J/K
Part APredict the sign of the entropy change, ΔS∘, for each of the reaction displayed.Drag the appropriate items to their respective bins.Ag+(aq)+Cl−(aq)→AgCl(s)2KClO3(s)→2KCl(s)+3O2(g)2N2O(g)→2N2(g)+O2(g)2Mg(s)+O2(g)→2MgO(s)C7H16(g)+11O2(g)→7CO2(g)+8H2O(g)H2O(l)→H2O(g)Part BCalculate the standard entropy change for the reaction2Mg(s)+O2(g)→2MgO(s)using the data from the following table:SubstanceΔH∘f (kJ/mol)ΔG∘f (kJ/mol)S∘ [J/(K⋅mol)]Mg(s)0.000.0032.70O2(g)0.000.00205.0MgO(s)-602.0-569.627.00Express your answer to four significant figures and include the appropriate units.ΔS∘ =
Calculate ΔG° for a reaction that has a ΔS° of 142.6 J/K and a ΔH° of 95.7 kJ occurring at standard conditions.
Use the data in Appendix B in the textbook to calculate ΔH∘ and ΔS∘ for each of the following reactions. From the values of ΔH∘ and ΔS∘, calculate ΔG∘ at 25 ∘C and predict whether each reaction is spontaneous under standard-state conditions. Part A 2SO2(g)+O2(g)→2SO3(g) Express your answer using four significant figures. ΔH∘ = kJ Part B Express your answer using four significant figures. ΔS∘ = J/K Part C Express your answer using four significant figures. ΔG∘ = kJ Part...
For reactions carried out under standard-state conditions, the equation ΔG = ΔH − TΔS becomes ΔG° = H° − TΔS°. Assuming ΔH° and ΔS° are independent of temperature, one can derive the equation: ln( K2 K1 ) = ΔH° R ( T2 − T1 T1T2 ) where K1 and K2 are the equilibrium constants at T1 and T2, respectively. Given that at 25.0°C, Kc is 4.63×10−3 for the reaction N2O4(g) longrightleftarrow 2NO2(g) ΔH° = 58.0 kJ/mol calculate the equilibrium constant...
For a certain chemical reaction, ΔH∘=−39.0kJ and ΔS∘=−84.0J/K Calculate ΔG∘ for the reaction at 298 K. Is the reaction spontaneous at 298 K under standard conditions?
A chemist measures the enthalpy change ΔH during the following reaction: 2KCl (s) + 3O2 (g) → 2KClO3 (s) ΔH=78.kJ Use this information to calculate ΔH in kJ for the following reactions: 6KCls + 9O2g → 6KClO3s 2KClO3s → 2KCls + 3O2g 4KClO3s → 4KCls + 6O2g
Determine ΔG°rxn using the following information. H2(g) + CO(g) → CH2O(g) ΔH°= +1.9 kJ; ΔS°= -109.6 J/K (Hint- What is the temperature when measuring standard heat of energy and change in entropy)
Determine ΔG°rxn using the following information. H2(g) + CO(g) → CH2O(g) ΔH°= +1.9 kJ; ΔS°= -109.6 J/K (Hint- What is the temperature when measuring standard heat of energy and change in entropy)