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For questions 10 and 11: (3 points cach) Solve the triangle 10. b = 7.c = 5, y = 37 e b Cs = SSA = LOS sinas sing sin & 5 Ein
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Answer #1

10. b = 7.c = 5, y = 37
Using sine rule:
с b sin 8 sin
\\\sin \beta = \frac{b\sin \gamma}{c} = \frac{7\sin 37\degree}{5} = \frac{7*0.601}{5}=0.8414 \\{\color{Blue} \beta = \sin^{-1}0.8414 = 57.4\degree}

From angle sum property:
Sum of the angle = 180
\\37\degree+ 57.4\degree + \alpha = 180\degree\\ \alpha= 85.6\degree

Again sing sine rule:
\frac{a}{\sin \alpha} = \frac{c}{\sin \gamma}
a = \frac{c\sin \alpha}{\sin \gamma} = \frac{7 \sin 57.4\degree}{\sin 37\degree} = \frac{7*0.842}{0.601} =9.8

2.
11.25.b = 6.c = 4
Using cosine rule:
\alpha = \cos^{-1}\left ( \frac{b^2+c^2-a^2}{2bc} \right )
\alpha = \cos^{-1}\left ( \frac{6^2+4^2-5^2}{2*6*4} \right ) =\cos^{-1}\frac{9}{16}
\alpha =55.77^{\circ \:}


\beta = \cos^{-1}\left ( \frac{a^2+c^2-b^2}{2ac} \right )
\beta= \cos^{-1}\left ( \frac{5^2+4^2-6^2}{2*5*4} \right ) =\cos^{-1}\frac{1}{8}
\beta =82.82^{\circ \:}


Now, from angle sum property:
sum of the angle = 180
\\57.77^{\circ \:} + 82.82^{\circ \:} +\gamma = 180^{\circ \:}\\ \gamma=180^{\circ \:}-140.59^{\circ \:}\\ \gamma = 41.41^{\circ \:}

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