Question

numbers 21,23,25

Objective 2: Solve a Triangle Using the Law of Sines (SSA) Ambiguous Case For Exercises 21-28. information is given about AABC. Determine if the information gives one triangle, two triangles, or no triangle. Solve the resulting triangle(s). Round the lengths of sides and measures of the angles to 1 decimal place if necessary. (See Examples 3-5) 21. b = 33, c = 25, B = 38° 22. b = 5.c = 12, C = 73° 23. a = 185, c = 132, C = 63° 24. b = 6, C = 12, B = 38° 25. a = 13, b = 18, A = 45° 26. a 3. b = 1, B = 17° 27. a = 132.5, b = 108.2, B = 13.1° 28. a = 48.8, c = 39.9, C = 22°

Answer 1

We know Sine nule SA Sing Since # a, 6 and, c are Sider $ A, B and C ane auglero @ Given that b- 33 ; c= 25; B= 38° Sing Sinc i en a5 /146=33 . Sin38 33 - Since 25 . . . 33 Sin C - Singgº *25 = 0.466 Ca Sin'(0.466) C = 27.8 x 28° . We know total angle in triangle = 180° A+B+ C= 180 A = 180°-38-28 => 114 > Sine Sin A > a = Sin Ax b sini 33 CS Scanned with Singga mScadea 48.96 49 SinB => Sin 114' x_33

@ a=185; c=132, C2.63' C=324 :. a=185 € - . .132 132 7. 785 SinA = Sin63" x 185 = 1.248 A Sin' (1-248) . No triangle with given information: a=13 ; b=18 ; A = 45° a3 A . 145h-18 18 Ba=13 C - SinB = Sinusex18 B = Sin \(0.97) = 78%25" ~ 78° Sum of angler A+B+C = 180 . 45+78°+c=1802 : C = 180°-123° = 57° Sina Sinc → .cz Sinc x SA => Sin (5+") x smis anned. VO= 15.4 =15 c . 13.