Question

Solve the triangle. For the sides, give an expression for the exact value of the length in terms of sine and approximate to 1 decimal place. 4 = 198.7 P62

Answer 1

Salati 178.7 -LR + +LQ = 180 591 +62 +0-180 10 - 54 Use Sin Rule Sink Sino Simpo Sin 59 Sin 54 z sin 67 te _1987_-_- length or pa z Sin 59x 198.7 Singu Vee St 54 = 0.85717 Sin 54 -0.80901 length P Q = 0.85717 * 198.7 = 210.5] 0.80901 length por RR z Sin 67 x 198.7 Sin 5y Tuse sin 67'= 0.92051 Leuth ea = 0.9205 x 198.7 = 22 6.08 - Be Q80901

Solution b=35 229 242 Use Sin Rule Sina sin & b Sing SinA = Sin42 = Sine 35 a 35 28 Tuse sin42 = 0.6691361 0.66913061 z Sinc 28 Since 0.6691306 x 29 35 Sinc'0.53530449 G232.36456 _A = 1105.631 Sin 105.63 = Sin 42 35 a = Sin 105.63 x 35 Sin 42" a = 0.9630x35 0.669130 length BC = 50.37]

Solution Ba: 5 Use Sin Rule Sina Sin B' e since 53 e Sina sini8 , sine 5 . 3 in = 5Sinis ---- Vse Sims_0.3090 5x0.3090 -0.515 Sin A, 0.515_ HA= 31 0:3090xC = Sinc - Sin 131 115-130 _0: 3690x6= 0.7547 length A Borc = 7.32718 - 7.32