Question

i need help with these 3 homework problems! thank you !

1. Solve the triangle. Round the lengths of sides and measures of the angles to 1 decimal place if necessary. 105 48° с b-27 Step 1: Find the exact measure of the missing angle. Step 2: Write one complete ratio and use the third piece of information to fill in part of a ratio. Step 3: Choose another set of ratios to solve, preferably one with no rounded values. 2 Solve the triangle with 4 -32°, B = 78°, and c-57. Round the lengths of the sides to 1 decimal place.

Answer 1

В Step I] Here 2A=480, LB=1050 IUS с we know Sum of all 1480 angles of triangle is 1 Isoc A b=27 so, LA+CB + <C = 180 < c = 180 - CA - LB I 180 - 48 - 105 LC = 35 27° Now we Know By law of sines, a b С sin A sin B sinc so a sin 48 = 27 sin los sin 27 =) a 27 0.9659 С 0.7431 0.4539 Step 2 : Now choose, 27 a 0.7431 0.9@659 =) a= 27 x 6.7431 6.9659 a = 20.772 Step 30:- Choose 27 С 0.9659 04539 27 x 0:4539 o.gg so = 12.6879 a) c = 12.6879 =) CP

2) Now, B LA = 32°, <B = 78° C=57 780 CS3 stepit]-cue know sum of cell angles of a triangle is 180° 320 C A So, LA+213 + < C = 180 ) Lc = 180 2A-LC Lc = 180 - 32-78 = 110° Lc = = 110° How, & By laws of sine, b C sina sin B sin c =) b 57 U sin 32 sin 78 sin 110 b a 0.5299 57 0.9781 0.9396 step 2:- =) now, chouse, a S7 0.5299 0.9396 a = 57 X0.5299 = 32.1459 0.9396 a = 32:1459 3! How, choose, b S7 0.9781 0.9396 Step - =) b= S7 0.9396 x 0.9781 =) | ь 59.3355