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(1 point) A random sample of 100 observations from a population with standard deviation 5.24 yielded...
(1 point) A random sample of 100 observations from a population with standard deviation 25.72 yielded...
(1 point) A random sample of 100 observations from a population with standard deviation 25.72 yielded a sample mean of 94.3. Part 1: Given that the null hypothesis is u = 90 and the alternative hypothesis is j > 90 using a = .05, find the following: (a) Test statistic = (b) P-value: Note: Round off the test statistic to 2 decimal places and the P-value to 4 decimal places.
(1 point) A random sample of 100 observations from a population with standard deviation 25.11 yielded a sample mean of 9...
(1 point) A random sample of 100 observations from a population with standard deviation 25.11 yielded a sample mean of 94.2 . 1. Given that the null hypothesis is
thank you for all the help! i appreciate everythjng! 1 2 3 (1 point) A random...
thank you for all the help! i appreciate everythjng!
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(1 point) A random sample of 100 observations from a population with standard deviation 8.31 yielded a sample mean of 91.5. Part 1: Part 2: Part 3: Given that the null hypothesis is j = 90 and the alternative hypothesis is #90 using a = .05, find the following: (a) Test statistic = (b) P-value: Note: Round off the test statistic to 2 decimal places and the P-value...
A random sample of 100 observations from a population with standard deviation 63 yielded a sample...
A random sample of 100 observations from a population with standard deviation 63 yielded a sample mean of 111. Complete parts a through c. a. Test the null hypothesis that y 100 against the alternative hypothesis that > 100, using a 0.05. Interpret the results of the test. Ho is rejected Ho is not rejected O Interpret the results of the test. Choose the correct interpretation below. O A. There is sufficient evidence to indicate the true population mean is...
Ch6 Sec2: Problem 3 PreviousProblem List Next (1 point) A random sample of 100 observations from...
Ch6 Sec2: Problem 3 PreviousProblem List Next (1 point) A random sample of 100 observations from a population with standard deviation 9.13 yielded a sample mean of 91.6 1. Given that the null hypothesis is--90 and the alternative hypothesis is μ > 90 using a) Test statistic- (b) P- value: (c) The conclusion for this test is: 05, find the following: A. Reject the null hypothesis B. There is insufficient evidence to reject the null hypothesis C. None of the...
A random sample of 100 observations from a population with standard deviation 76 yielded a sample...
A random sample of 100 observations from a population with standard deviation 76 yielded a sample mean of 114. Complete parts a through c below. a. Test the null hypothesis that u = 100 against the alternative hypothesis that u > 100, using a = 0.05. Interpret the results of the test. What is the value of the test statistic? und to two decimal places as needed.) Find the p-value. p-value = (Round to three decimal places as needed.) State...
thank you for help! it means a lot to me ! and can u please underline...
thank you for help! it means a lot to me ! and can u please
underline or circle the answers. thank you
1
2
(1 point) A random sample of 100 observations from a population with standard deviation 13.83 yielded a sample mean of 92.3. Given that the null hypothesis is u = 90 and the alternative hypothesis is u > 90 using a = .05, find the following: (a) Test statistic: (b) P-value: DOO The conclusion for this test...
im so grateful for all the help! thank you in advance !! this means so much...
im so grateful for all the help! thank you in advance !! this
means so much to me you havw no idea
1
2
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4
At least one of the answers above is NOT correct. (1 point) (a) Find the P-value for the test statistic z = -1.32 for the following null and alternative hypotheses: Ho: The population mean is 18. H : The population mean is less than 18. The P-value is 0.000347 (b) Find the P-value for...
Homework4: Problem 2 Previous Problem Problem List Next Problem (6 points) A random sample of 100...
Homework4: Problem 2 Previous Problem Problem List Next Problem (6 points) A random sample of 100 observations from a population with standard deviation 23.75 yielded a sample mean of 94.5. 1. Given that the null hypothesis is H = 90 and the alternative hypothesis is u > 90 using a = .05, find the following: (a) Test statistic = (b) P-value: (c) The conclusion for this test is: A. There is insufficient evidence to reject the null hypothesis B. Reject...
Suppose a random sample of 100 observations from a binomial population gives a value of p...
Suppose a random sample of 100 observations from a binomial population gives a value of p = 0.45 and you wish to test the null hypothesis that the population parameter p is equal to 0.40 against the alternative hypothesis that p is greater than 0.40. Complete parts a through c. a. Noting that p = 0.45, what does your intuition tell you? Does the value of p appear to contradict the null hypothesis? O A. Yes, because p satisfies Hg:p>0.40...
(1 point) A random sample of 100 observations from a population with standard deviation 25.72 yielded a sample mean of 94.3. Part 1: Given that the null hypothesis is u = 90 and the alternative hypothesis is j > 90 using a = .05, find the following: (a) Test statistic = (b) P-value: Note: Round off the test statistic to 2 decimal places and the P-value to 4 decimal places.
thank you for all the help! i appreciate everythjng!
1
2
3
(1 point) A random sample of 100 observations from a population with standard deviation 8.31 yielded a sample mean of 91.5. Part 1: Part 2: Part 3: Given that the null hypothesis is j = 90 and the alternative hypothesis is #90 using a = .05, find the following: (a) Test statistic = (b) P-value: Note: Round off the test statistic to 2 decimal places and the P-value...
A random sample of 100 observations from a population with standard deviation 63 yielded a sample mean of 111. Complete parts a through c. a. Test the null hypothesis that y 100 against the alternative hypothesis that > 100, using a 0.05. Interpret the results of the test. Ho is rejected Ho is not rejected O Interpret the results of the test. Choose the correct interpretation below. O A. There is sufficient evidence to indicate the true population mean is...
Ch6 Sec2: Problem 3 PreviousProblem List Next (1 point) A random sample of 100 observations from a population with standard deviation 9.13 yielded a sample mean of 91.6 1. Given that the null hypothesis is--90 and the alternative hypothesis is μ > 90 using a) Test statistic- (b) P- value: (c) The conclusion for this test is: 05, find the following: A. Reject the null hypothesis B. There is insufficient evidence to reject the null hypothesis C. None of the...
A random sample of 100 observations from a population with standard deviation 76 yielded a sample mean of 114. Complete parts a through c below. a. Test the null hypothesis that u = 100 against the alternative hypothesis that u > 100, using a = 0.05. Interpret the results of the test. What is the value of the test statistic? und to two decimal places as needed.) Find the p-value. p-value = (Round to three decimal places as needed.) State...
thank you for help! it means a lot to me ! and can u please
underline or circle the answers. thank you
1
2
(1 point) A random sample of 100 observations from a population with standard deviation 13.83 yielded a sample mean of 92.3. Given that the null hypothesis is u = 90 and the alternative hypothesis is u > 90 using a = .05, find the following: (a) Test statistic: (b) P-value: DOO The conclusion for this test...
im so grateful for all the help! thank you in advance !! this
means so much to me you havw no idea
1
2
3
4
At least one of the answers above is NOT correct. (1 point) (a) Find the P-value for the test statistic z = -1.32 for the following null and alternative hypotheses: Ho: The population mean is 18. H : The population mean is less than 18. The P-value is 0.000347 (b) Find the P-value for...
Homework4: Problem 2 Previous Problem Problem List Next Problem (6 points) A random sample of 100 observations from a population with standard deviation 23.75 yielded a sample mean of 94.5. 1. Given that the null hypothesis is H = 90 and the alternative hypothesis is u > 90 using a = .05, find the following: (a) Test statistic = (b) P-value: (c) The conclusion for this test is: A. There is insufficient evidence to reject the null hypothesis B. Reject...
Suppose a random sample of 100 observations from a binomial population gives a value of p = 0.45 and you wish to test the null hypothesis that the population parameter p is equal to 0.40 against the alternative hypothesis that p is greater than 0.40. Complete parts a through c. a. Noting that p = 0.45, what does your intuition tell you? Does the value of p appear to contradict the null hypothesis? O A. Yes, because p satisfies Hg:p>0.40...
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