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Suppose a random sample of 100 observations from a binomial population gives a value of p = 0.45 and you wish to test the nul

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Answer #1

a)
Option C

b)
Rejection Region
This is right tailed test, for α = 0.05
Critical value of z is 1.645.
Hence reject H0 if z > 1.645

Test statistic,
z = (pcap - p)/sqrt(p*(1-p)/n)
z = (0.45 - 0.4)/sqrt(0.4*(1-0.4)/100)
z = 1.02

Do not reject H0
option B

c)
P-value Approach
P-value = 0.1539
As P-value >= 0.05, fail to reject null hypothesis.

option C

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