Question

The data on the right represent the number of the muliple-delivery birth (three or more habe in particule year for women 15 to 5 years old. Use the date to complete parte a through the below Nawrot to Age 97 35 TA 155 la) Determine the probably thw a randomly selected multiple for women 15-54 years old involved a mother 30 to 39 years old PC3039-0 Type an integer or decimal rounded to the decimal places as needed (b) Determine the probably that a randomly selected multiple it for woman 15 years old nada mother who was not 30 to 3 years old Pinot 30 to 39 (Type winteger or decimal rounded to three decimal places as needed c) Deline the probability that a randomly selected muliebth for won 15 54 year old involved mother who less than 15 years old Pfless than 45 Type an integer or decimal rounded to three decimal places as needed (d) Determine the probability that and selected with or woman 15 54 years old Involved me who was at least 2 years old artista? Find the probability that a randomly selected mutil birth for women 15.54 years old involved a mother who was at least 10 years old Plot east 40)-2 Type an integer or decimal rounded to three decimal places a meded) Interpret this result Slect the corred choice below and in the answer box to complete your choice Types whole number OA 1000 multiple bites for women 15-54 years old wandomly selected any of them would be mother who was atost 4 yes okt OB. 1000 mutiple births for wen 15-54 years old were randomly selected, we would expect of them to involve a mother who was a year old Is a multiple birth involving a mother who was at least 40 years old unusua OA Yes, because the probability of multiple birth involving a mother who was a 40 years old is a than 05 OB Yes, because the probabilty of a shiple bich involving a mother who was a wastas OC No, because the probability of a multiple birth imoving a mother who was at last years old is less than a OD. Nobecause the probability of a multiple birth involving mother who was at least 10 years old is greater than 0.05 Click to select your answers)

Answer 1

Probability= No. of desired outcomes / Total outcomes

Age	Freq
15-19	92
20-24	505
25-29	1634
30-34	2840
35-39	1855
40-44	375
45-54	118
total	7419

a)

P(age 30-39): ca be from age group 30-34 or 35-39

P(age 30-39) = P(age 30-34) + P(age 35-39)

=(2840 / 7419) + 1855 / 7419

Ans: 0.63284

b)

Someone who was not 30-39 means complementary of 30-39

P(not 30-39) = 1- P(30-39) ..............rule of total probability

=1 - 0.63284

ans: 0.3672

alternative : add all age groups except 30-39 = 2724

P(not 30-39) = 2724 / 7419

c)

Someone less than 45 means all the age group uptil 45

P(less than 45) :

15-19	92
20-24	505
25-29	1634
30-34	2840
35-39	1855
40-44	375

less than 45 =7301

P(less than 45) = 7301 / 7419

Ans: 0.9841

d)

To be atleast 40 years means 40 or above 40. so we include that age from 40

40-44	375
45-54	118

at least 40 = 493

P(at least 40) = 493 / 7419

Ans: 0.0665

d) This is means if 1 selected then 0.0665 chance that the women is at least 40. For 1000

Expected at least 40 out of 1000 = 1000 * 0.0665

= 66.45

=66

Option B: 66

This is an expectation and not actual value.

The probability is unusal if p < 0.05

Since 0.0665 > 0.05, this is not unusal

Option D