If you mix 100. mL of 0.11 M HCl with 50.0 mL of 0.22 M NH3, what is the pH of the resulting solution? For NH4+, Ka = 5.6 x 10-10
A. 4.63
B. 8.37
C. 9.37
D. 5.19
E. 6.02
We need at least 10 more requests to produce the answer.
0 / 10 have requested this problem solution
The more requests, the faster the answer.
What is the pH of the solution that results from adding 22.0 mL of 0.11 M HCl to 25.3 mL of 0.41 M NH3? ( Ka for ammonium ion is 5.6 x 10^-10.) pH= ?
If you mix 100.0 mL of 0.125 M HCl (strong acid) with 50.0 mL of 0.175 M NaOH (strong base) what will be the pH of the resulting solution? Have you reached the endpoint of the reaction (circle your answer)? YES NO Explain your answer:
Review Problem 16.110 A buffer is prepared containing 0.11 M NH3 and 0.44 M NH4+. Calculate the pH of the buffer using the Ka for NH4+. Ka = 5.6 x 10-10 for NH4+. pH =
The sample of 20.00 mL of 0.015 M NH3 is titrated with 0.030 M HCl. (a) Show the reaction between NH3 and H+. (1 point) (b) Find the volume of 0.030 M HCl needed to reach the equivalence point. (1 point) (c) Show the reaction of hydrolysis of product from the step (a). (1 point) (d) Calculate the pH at the equivalence point (Ka of NH4+ is 5.6 x 10–10). (1 point) Hint: Use Tables. Example of answer: (a) [show...
The titration of 50.00 mL solution of a 0.1 M OAc- with 0.2 M HCl. OAc- is a weak base. Ka for acetic acid = 1.75 * 10^-5. a) Calculate the pH of the 50.0 mL of 0.1 M OAc- solution before the addition of any HCl. b) Calculate the pH of the resulting solution after the addition of 5.0 mL of 0.2 M HCl to the 50.0 mL of 0.1 M OAc- solution. c) Calculate the pH of the resulting...
calculate the pH when 50.0 mL of 0.4 M NH3 is mixed with 5.00 mL of 0.8 M HCl. ( The ka of ammonia is 1.77 x10^-5.) KaKb=Kw (Ka)(Kb)=1.00 x 10^-14
A 50.0 mL sample of 0.11 M nitrous acid is titrated with 0.22 M NaOH. Calculate the pH to one decimal place when the following volumes of NaOH have been added. 0.00 mL 22.0 mL 25.0 mL 33.0 mL
A solution is prepared by adding 20.0 mL of 0.15 M HCl to 80.0 mL of 0.20 M NH3. Ka(NH4+)= 5.8 x 10-10 a. Is this solution a buffer? Why or why not? b. What is the pH of the solution?
What volume of 0.200 M HCl must be added to 500.0 mL of 0.250 M NH3 to have a buffer with a pH of 9.04? K, for NH4* is 5.6 x 10-10 Volume = L Submit Answer Try Another Version 2 item attempts remaining
Consider the titration of 50.0 mL of 0.133 M NH3 (a weak base with Kb = 1.76 x 10-5 ) with 0.223 M HCl (a strong acid). Calculate the pH of the solution at each of the following points: 1. What is the pH of the solution before the titration is begun? 2. What is the pH of the solution after the addition of 15 mL of HCl? 3. What is the pH of the solution at the equivalence point?...