The sample of 20.00 mL of 0.015 M NH3 is titrated with 0.030 M HCl. (a)...
The sample of 20.00 mL of 0.015 M NH3 is titrated with 0.030 M HCl.
(a) Show the reaction between NH3 and H+. (1 point)
(b) Find the volume of 0.030 M HCl needed to reach the equivalence point. (1 point)
(c) Show the reaction of hydrolysis of product from the step (a). (1 point)
(d) Calculate the pH at the equivalence point (Ka of NH4+ is 5.6 x 10–10). (1 point)
Hint: Use Tables.
Example of answer: (a) [show the reaction]; (b) Volume of HCl solution = [type your calculator answer without rounding] L; (c) [show the reaction]; (d) pH at the equivalence point = [type your answer with two digits after decimal].
Homework Answers
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The sample of 20.00 mL of 0.015 M NH3 is titrated
with 0.030 M HCl.
(a)...
A 20.00 mL sample of 0.150 M NH3 is being titrated with 0.200 M HCl. What...
A 20.00 mL sample of 0.150 M NH3 is being titrated with 0.200 M HCl. What is the pH after 20.00 mL of HCl has been added? Kb of NH3 = 1.8 × 10−5
A 10.0 mL sample of 0.25 M NH3(aq) is titrated with 0.20 M HCl(aq) (adding HCl to NH3
1)A 10.0 mL sample of 0.25 M NH3(aq)
is titrated with 0.20 M HCl(aq) (adding HCl to
NH3). Determine which region on the titration curve the
mixture produced is in, and the pH of the mixture at each volume of
added acid.Kb of NH3 is 1.8 ×
10−5.Henderson–Hasselbalch equation:Part a):1) After adding 10 mL of the HCl solution, the
mixture is [ Select ] ["at", "before", "after"] the
equivalence point on the titration curve.2) The pH of the solution after...
Calculate the pH at the equivalence point when 25.0mL of 0.100M NH3 is titrated with 0.100M HCl. The reaction is...
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Question 6 1 pts A 10.0 mL sample of 0.25 M NH3(aq) is titrated with 0.20 M HCl(aq) (adding HCl to NH3). Determine whic...
Question 6 1 pts A 10.0 mL sample of 0.25 M NH3(aq) is titrated with 0.20 M HCl(aq) (adding HCl to NH3). Determine which region on the titration curve the mixture produced is in, and the pH of the mixture at each volume of added acid. Ko of NH3 is 1.8 x 10-5 Henderson-Hasselbalch equation: pH = pka + log og HCI NH, NH3- Parta): 1) After adding 10 mL of the HCl solution, the mixture is (Select] the equivalence...
Sketch a pH titration curve if 100.0 mL of 0.125 M NH3 solution is titrated with...
Sketch a pH titration curve if 100.0 mL of 0.125 M NH3 solution is titrated with 0.15M HCl. Note the following three items on the curve. K, for NHa 1.8 x 105 pH= Calculate the starting pH (no HCl added) vol (mL)= Calculate the volume of HCl added to reach the equivalence point pH = Calculate the pH at the equivalence point.
2. 20.00 mL of 0.270 M HA (K. = 7.2 x 10-4) was titrated with 0.300...
2. 20.00 mL of 0.270 M HA (K. = 7.2 x 10-4) was titrated with 0.300 M sodium hydroxide (3 + 3 + 2 + 3 + 3 + 3 + 12 = 29 points) a) Write the titration equation and calculate volume of NaOH needed to reach the equivalence point. ml b) At what volume of the titrant would pH=pKa? Why? c) pH at the equivalence point when the acid and base are neutralized will be ..choose one of...
1.) 20.00 mL of 0.11 M benzoic acid (C6H5COOH, Ka = 6.3x10-5) is titrated with 0.25...
1.) 20.00 mL of 0.11 M benzoic acid (C6H5COOH, Ka = 6.3x10-5) is titrated with 0.25 M NaOH. What volume of base is required to reach the equivalence point in the titration? 2.) Calculate pH at each of the following points in the titration. a) 4.00 mL b) 8.80 mL
1. A 40.0 mL sample of 0.205 M NH3(aq) is titrated with 0.250 M HBr(aq) at...
1. A 40.0 mL sample of 0.205 M NH3(aq) is titrated with 0.250 M HBr(aq) at 25 oC. The pKb for NH3 is 4.74 at 25 oC. (a) (4 Marks) Using all correct symbols and arrows, write the complete balanced chemical equation and net ionic equation for the neutralization reaction upon which this titration is based. (b) (4 Marks) What is the pH of the initial solution of NH3(aq)? Write the appropriate balanced equilibrium reaction that governs the pH of...
Calculate the pH at the equivalence point when 25.0mL of 0.100M NH3 is titrated with 0.100M...
Calculate the pH at the equivalence point when 25.0mL of 0.100M NH3 is titrated with 0.100M HCl. The reaction is given as follows : NH3 + H30+ -> NH4+ + H20 Show complete solution . Will rate your answer. Draw titration curve and label first and second equivalence point.
A 40.0 mL sample of 0.150 M HNO2 (Ka = 4.60 x 10-4) is titrated with...
A 40.0 mL sample of 0.150 M HNO2 (Ka = 4.60 x 10-4) is titrated with 0.200 M KOH. Calculate: a. the pH after adding 10.00 mL of KOH b. the pH at one-half the equivalence point c. the pH after adding 20.00 mL of KOH d. the volume required to reach the equivalence point e. the pH at the equivalence point f. the pH after adding 45.00 mL of KOH
1)A 10.0 mL sample of 0.25 M NH3(aq)
is titrated with 0.20 M HCl(aq) (adding HCl to
NH3). Determine which region on the titration curve the
mixture produced is in, and the pH of the mixture at each volume of
added acid.Kb of NH3 is 1.8 ×
10−5.Henderson–Hasselbalch equation:Part a):1) After adding 10 mL of the HCl solution, the
mixture is [ Select ] ["at", "before", "after"] the
equivalence point on the titration curve.2) The pH of the solution after...
Question 6 1 pts A 10.0 mL sample of 0.25 M NH3(aq) is titrated with 0.20 M HCl(aq) (adding HCl to NH3). Determine which region on the titration curve the mixture produced is in, and the pH of the mixture at each volume of added acid. Ko of NH3 is 1.8 x 10-5 Henderson-Hasselbalch equation: pH = pka + log og HCI NH, NH3- Parta): 1) After adding 10 mL of the HCl solution, the mixture is (Select] the equivalence...
Sketch a pH titration curve if 100.0 mL of 0.125 M NH3 solution is titrated with 0.15M HCl. Note the following three items on the curve. K, for NHa 1.8 x 105 pH= Calculate the starting pH (no HCl added) vol (mL)= Calculate the volume of HCl added to reach the equivalence point pH = Calculate the pH at the equivalence point.
2. 20.00 mL of 0.270 M HA (K. = 7.2 x 10-4) was titrated with 0.300 M sodium hydroxide (3 + 3 + 2 + 3 + 3 + 3 + 12 = 29 points) a) Write the titration equation and calculate volume of NaOH needed to reach the equivalence point. ml b) At what volume of the titrant would pH=pKa? Why? c) pH at the equivalence point when the acid and base are neutralized will be ..choose one of...
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