Question

Vinegar is 5.0 % m/v acetic acid (CH3COOH), this means that there is 5.0 g acetic...

Vinegar is 5.0 % m/v acetic acid (CH3COOH), this means that there is 5.0 g acetic acid per 100.0 mL solution. Use dimensional analysis to calculate what the molarity (mol/L) would be of this solution.

0 0
Add a comment Improve this question Transcribed image text
Request Professional Answer

Request Answer!

We need at least 10 more requests to produce the answer.

0 / 10 have requested this problem solution

The more requests, the faster the answer.

Request! (Login Required)


All students who have requested the answer will be notified once they are available.
Know the answer?
Add Answer to:
Vinegar is 5.0 % m/v acetic acid (CH3COOH), this means that there is 5.0 g acetic...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Similar Homework Help Questions
  • Vinegar is sold as % acidity which means a weight/volume or w/v% calculation. The density of...

    Vinegar is sold as % acidity which means a weight/volume or w/v% calculation. The density of acetic acid is 1.05 g/ml and water is (effectively) 1.0 g/ml. Recollect (from CHMY121) the %w/v refers to a solution with a certain mass of additive made up to 100 mL with the addition of (in this case) water;                                or % m/v= (grams of solute /  100 mL solution)  ×100 The molar mass of Acetic Acid is 60.052 g/mol. What is the molarity of...

  • 4. Vinegar is a solution of acetic acid. Acetic acid has a 1:1 ratio when reacted...

    4. Vinegar is a solution of acetic acid. Acetic acid has a 1:1 ratio when reacted with NaOH. a. Suppose that the molarity of acetic acid in vinegar is 0.5 M, how many grams of acetic acid are present in the 5 ml of vinegar solution used in the titration? (molar mass of acetic acid = 60 g/mol). b. If vinegar has a density of 1.01 g/mol. Calculate the % of acetic acid in vinegar by mass. 5. 50 ml...

  • Vinegar is a solution of acetic acid. Acetic acid has a 1:1 ratio when reacted with...

    Vinegar is a solution of acetic acid. Acetic acid has a 1:1 ratio when reacted with NaOH. a. Suppose that the molarity of acetic acid in vinegar is 0.5 M, how many grams of acetic acid are present in the 5 ml of vinegar solution used in the titration? (molar mass of acetic acid = 60 g/mol). b. If vinegar has a density of 1.01 g/mol. Calculate the % of acetic acid in vinegar by mass.

  • 3. Calculate the molarity of the acetic acid in the vinegar solution for each trial. 4....

    3. Calculate the molarity of the acetic acid in the vinegar solution for each trial. 4. Calculate the average molarity. 5. Calculate the %mass acetic acid in the vinegar solution. 6. The vinegar for this experiment was store bought Heinz Vinegar. Does your answer to question 5 seem reasonable? 7. Write and appropriate lab procedure for this experiment. Use the data to inform your procedure. % Mass #DIV/0! Name 9 M NaOH Density (g/mL) 0.5167 1.002 Trial 1 Trial 2...

  • 6. Vinegar is 5.00% (m/v) acetic acid (CH3COOH). How many milliliters of vinegar would you need...

    6. Vinegar is 5.00% (m/v) acetic acid (CH3COOH). How many milliliters of vinegar would you need to react with an excess of baking soda (NaHCO3) in order to generate 10.0 L of carbon dioxide gas at 1.05 atm and a temperature of 25.0°C?

  • 5% acetic acid in water. This is a volume percent (v/v) which means there are 5...

    5% acetic acid in water. This is a volume percent (v/v) which means there are 5 4. Vinegar is a solution of approximately of acetic acid per 100 mL. of vinegar. The density of acetic acid is 1.05 g/mL. Use stoichiometry to determine how man grams of acetic acid are in 15.0 mL of vinegar. are the molar masses of the two reactants, acetic acid and sodium bicarbonate? Show all work

  • a-c 5, Vinegar should contain more than 4% acetic acid (CHCOOH, molar mass 60.0 g mor)...

    a-c 5, Vinegar should contain more than 4% acetic acid (CHCOOH, molar mass 60.0 g mor) 25.0 mL of vinegar are diluted to 100.0 mL and 10.0 mL samples of this solution are titrated against 0.100 mol L-NaOH solution. An average of 18.1 mL NaOH are required to neutralize the vinegar. You will need to calculate the concentration of the diluted solution and hence the percentage concentration of acetic acid in the original vinegar via the following questions: CH COOH(aq)...

  • KOH (concentration = 0.2205 M) is used in a titration to determine the amount of acetic...

    KOH (concentration = 0.2205 M) is used in a titration to determine the amount of acetic acid (CH3COOH) in vinegar! 50 mL of vinegar was diluted to 500 mL in a volumetric flask. 25 mL of the diluted vinegar solution was titrated five times with the KOH. The concentration of acetic acid in the DILUTED vinegar sample is 0.2171 M Calculate the concentration of acetic acid in the ORIGINAL vinegar solution Give your answer in g/L MM CH3COOH = 60.05...

  • 6. Vinegar is 5.00% (m/v) acetic acid (CH3COOH). How many milliliters of vinegar would you need...

    6. Vinegar is 5.00% (m/v) acetic acid (CH3COOH). How many milliliters of vinegar would you need to react with an excess of baking soda (NaHCO3) in order to generate 10.0 L of carbon dioxide gas at 1.05 atm and a temperature of 25.0°C? 7. Shown below is the aqueous reaction of KNOX, HCl, and SnCl2. 2 KNO2 (aq) + 6 HCl(aq) + 2 SnCl2 (aq) → 2 SnCla (aq) + N20 (g) + 3 H20 (1) + 2 KCl (aq)...

  • . Assume that vinegar is 5% acetic acid (by mass) at a density of 1.01 g...

    . Assume that vinegar is 5% acetic acid (by mass) at a density of 1.01 g mL-1. This means that 100 mL of vinegar you would have 5.05 g of acetic acid. Calculate the molar amounts of acetic acid and sodium bicarbonate that you will use in this experiment.

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT