Question

How does the DeBroglie wavelength of the electron in the ground state of a hydrogen atom compare to the DeBroglie wavelength of the electron when it's in a 2p state? The DeBroglie wavelengths of the two electrons are equal. The DeBroglie wavelength of the electron in the ground state is greater than that of the electron in a 2p state. The DeBroglie wavelength of the electron in the ground state is less than that of the electron in a 2p state. There is no way to compare the DeBroglie wavelengths of these two electrons.

Answer 1

$\lambda$ = h / mv

where

v is a function of 1/n

where n is orbit number

so,

$\lambda$ is a direct function of n. This means as we go up from ground state, $\lambda$ increase

for example - The de - Broglie wavelength associated with the electron in the n=4 level is four times the de - Broglie wavelength in the ground state

so,

option (3) is fine !!