Question

How does the DeBroglie wavelength of the electron in the ground state of a hydrogen atom compare to the DeBroglie wavelength of the electron when it's in a 2p state? The DeBroglie wavelengths of the two electrons are equal. The DeBroglie wavelength of the electron in the ground state is greater than that of the electron in a 2p state. The DeBroglie wavelength of the electron in the ground state is less than that of the electron in a 2p state. There is no way to compare the DeBroglie wavelengths of these two electrons.

Answer 1

Multiple questions posted, so answering only the first question:

Debroglie wavelength=h/(mv) where h is Planck's constant, m is mass of the particle and v is its velocity. So, if velocity increases, debroglie wavelength decreases.

Now, as the principle quantum number increases, velocity of the electron decreases. So, velocity of an electron in 2p is less than that in ground state.

So, debroglie wavelength of an electron in ground state is less than that of an electron in 2p state(option 3).