Question

How does the DeBroglie wavelength of the electron in the ground state of a hydrogen atom compare to the DeBroglie wavelength of the electron when it's in a 2p state? The DeBroglie wavelengths of the two electrons are equal. The DeBroglie wavelength of the electron in the ground state is greater than that of the electron in a 2p state. The DeBroglie wavelength of the electron in the ground state is less than that of the electron in a 2p state. There is no way to compare the DeBroglie wavelengths of these two electrons.

Answer 1

debroglie wavelength given by:

wavelength = h / momentum = h / (2 * m *E)^1/2

since 2p state electron has higher energy than ground state electron . Therefore, the debroglie wavelength in ground state is greater than the 2p state electron.