Question

the length of a rectangular garden is 7 feet more than three times the width. the perimeter of the garden is 86 feet. find the area of the garden.

Answer 1

D then acco C b B A ? let A B C D be the Rectangular gardent and its coidth is b according to question, the length of garden is 7 feet more than three l=?= 36 +7 times the width. So, it length th is denoted by l , then l = 3 xb +7 36+7 1 AISO, perimeter = 86 feet (Given) We know that perimeter of Rectangle is P (l+b) Where l&b are Side lengths of Rectangulas perimeter = = 86 feet >> 2 ( 36+7 + b) = 86 feet = 86 feet (66 +26) + 14 = 86 feet 8b + 14 = 86 feet + 86= (86-14) feet (setetracting 14 both sides o 86 = 72 feet b- 72 feet (dividing by ig' both both sides) (ii) - bag feet Hence = 36 +7 ( by ©)) 6bt 14 +2b

Date Page b = 3b +7 (by (i)) .. l = 3x9 +7 27+7 = 34 ft (6=9, by vo Now, we know that the formula for calculating area of Rectangle is Area (A) = length (l) x coldth (6) A = (36+7) xb > A = (34 ft)x (9 ft) area of garden is 306 (ft) 306 (ft). Ansever Hence

Answer 2

SOLUTION :

Let length of garden be L and width be W .

So, L = 3W + 7 

Perimeter, P = 2L + 2W = 2(3W + 7) + 2W = 8W + 14 

=> 86 = 8W + 14

=> 8W = 86 - 14 = 72

=> W = 72/8 = 9 ft

=> L = 3 * 9 + 7 = 34 ft 

So, Area of the garden 

= 34 * 9

= 306 sq. ft. (ANSWER).