Length = L
Width = W = L+4
Perimeter = 2(W+L)
= 2(L+4+L)
24 = 2(2L+4)
12 = 2L+4
6 = L+2
4 = L
Length = 4 ft
Width = 4+4 = 8 ft
The perimeter of a rectangular window is 24 feet. The width of the window is 4...
one more screenshot just to make it clear please provide me the answer The perimeter of a rectangular window is 32 feet. The width of the window is 6 feet more than the length. What are the dimensions of the window? The length of the window is feet. The width of the window is feet. The perimeter of a rectangular window is 32 feet. The width of the window is 6 feet more than the length. What are the dimensions...
The length of a rectangular window is 5 feet more than its width, w. The area of the window is 36 square feet. We wish to find both the length and width of the window. Please do the following: Write an equation that could be used to find the dimensions of the window USING ONLY ONE VARIABLE (w). Put that equation in standard form (so that all terms are on one side of the equation together equal to zero). FACTOR...
the length of a rectangular garden is 7 feet more than three times the width. the perimeter of the garden is 86 feet. find the area of the garden.
The perimeter of a rectangular outdoor patio is 76 ft. The length is 4 ft greater than the width. What are the dimensions of the patio?
The length of a new rectangular playing field is 4 yards longer than double the width. If the perimeter of the rectangular playing field is 350 yards, what are its dimensions? The width is yards. The length is yards.
If the perimeter of a tennis court is 228 feet and the length is 6 feet longer than twice the width, then what are the length and width?
The length of a rectangular piece of property if 1 foot more than twice the width. If the perimeter is 302 feet, find the length and width.
Question 15 The perimeter of a rectangular swimming pool is 182 yards. The width of the pool is 7 yards more than five times the length. Find the length and the width. Provide your answer below: L= yards, W= yards FEEDBACK
A rectangular field is three times as long as it is wide. If the perimeter of the field is 160 yards, what are the field's dimensions? The width of the rectangular field is The length of the rectangular field is
You may remember that the perimeter of a rectangle is P=2(W+L) where W is the width and L is the length. Suppose that the perimeter of a rectangle is 44 feet, and the length is 12 feet more than the width. Find the width of the rectangle, in feet.