Question

Monochromatic light strikes a diffraction grating at normal incidence before illuminating a screen 2.50 m away. Part A If the first-order maxima are separated by 1.53 m on the screen, what is the distance between the two second-order maxima? Express your answer to three significant figures. ΑΣΦ ? y2 = 3.36 m Submit Previous Answers Request Answer X Incorrect; Try Again; 5 attempts remaining

Answer 1

# We know, from double - slit experiment dsin (On) =ny Where n = whole number Sinon) = 2 0 d= distance bet the slits. nx Step Given, difference befor the yo = 1.53 first- onder maximas. = 0.765 m step-2 We know, yn =nL tam (on) 12 Where, L= distance bet slits and screen n=1, first onder maxima. Thun, y = =htana Given. L=2.5m >> 01 = tant(1) [L=25m tant C 0.765 2.5 17.0149 step-3 from the 1st eqush Sino) = d
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So, - Sin (17.014) -0.2926 3 Again from equr 0 Sino) = 21 O2 = Sit Sint (2/2) 0.2926) id O2= Sint (2 2x o = 35.817° them from egun e the distance beth two second order maxima , 72= 2xLx tum (02) - 2x215 x fan (35.817) - 3.6083 m (Am) -
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