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A person, with his ear to the ground, sees a huge stone strike the concrete pavement. A moment later two sounds are heard fromy Two violin strings are tuned to the same frequency, 294 Hz . The tension in one string is then decreased by 1.7 %. Part A

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Use the speed of sound in air and concrete to find the required impact distance as shown below. The sound travels the same distance in concrete and air.A) The ear is at distance d from the impact, So, time taken for sound in air is, ta {va = speed of sound in air Va d - time t

2) A) fa f יה mv 294 Hz 2L V = Fr u=m/L New tension F F = ll q Fq X 1.7 100 0.983 FT new speed Vs 11 0.983 Fq - c Jo.983 M (

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