Will the following reaction proceed as written? Show work.
2 NADP + + H+ + 2e- --> 2 NADPH + 2 O2 + 2 H+
O2 + 4 e- + 4 H+ --> H2O E0'= 0.815 V
NADP+ + H+ + 2 e- --> NADPH E0'= -0.320 V
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Will the following reaction proceed as written? Show work. 2 NADP + + H+ + 2e-...
glutathione reductase catalyzes the following reaction: GSSG (oxidized glutathione) + NADPH+H ----> 2GSH (reduced Glutathione)+ NADP+. NAD+ + H + 2e --> NADH E= -0.32 V NADP+ + H + 2e NADPH E= -0.32 V GSSG + + 2H + 2e 2GSH E= -0.23 V a) Calculate delta G for glutathione reductase reaction in the direction shown using E values above b) Suppose that a cell contained an isoform of glutathione reductase that used NADH instead of NADPH...
Using the values listed in the table provided, determine the deltaG associated with teh reaction listed below: NADPH + 1/2O2 + H+ --> NADP+ +H2O (V) Half-Reaction 0.815 O, 2 H 2 e H3O SO 2 H+ 2 e SO H2O 0.48 NO3 2 H 2 e NO3 0.42 Cytochrome a3 (Fe3+) e cytochrome a (Fe2+) 0.385 O2 (g) 2 H+ 2 e 2O2. 0.295 Cytochrome a (Fes e cytochrome a (Fe2+) 0.29 Cytochrome c (Fe3+) e cytochrome c (Fe...
According to the following reaction, how many photons are necessary to synthesize a pentose? 2 H2O + 2 NADP + 8 photons -> 2 NADPH H + 2H + O2
Select all of the following half reactions that require energy (work) to proceed as written. Select all of the following half reactions that require energy (work) to proceed as written. 0 (not balanced) O NADH + H+ → NAD+ + 2H NAD+ + 2H → NADH + H+ ATP + H2O → ADP + Pi 0 人H (not balanced) glucose + inorganic phosphate → glucose-6-phosphate + H2O
The following reaction will not proceed as written. Clearly explain why this reaction will not occur. The following reaction will not proceed as written. Clearly explain why this reaction will not occur. 1. LDA ix 2. Br
Calculate E0cell (in volts) for the reaction as written: 4 Al(s) + 3 O2(g) + 12 H+(aq) --> 4 Al3+(aq) + 6 H2O Data: O2 + 4 H+ + 4 e- --> 2 H2O E0red = +1.22 V Al3+ + 3 e- --> Al E0red = -1.66 V a. +0.44 b. -2.98 c. +2.88 d. +2.98 e. -0.44
If anyone can provide help that would be great! Thanks! Calculate the actual AG for the reaction in which molecular oxygen is reduced by the electron carrier NADH. 1202 + NADH+H→ H2O + NAD The concentrations of O2 and NADH are 1.00M and H20 and NAD are 0.100M. The relevant half reactions and their E values are: (1) % O2 + 2H+ +2e → H20 (2) NAD + H+ +2e → NADH E' = 0.816 V E' = -0.320 V
The following reaction will not proceed as written. Clearly explain why this reaction will not occur. The following reaction will not proceed as written. Clearly explain why this reaction will not occur. CH3CI AICI:
6. The reaction 2 H + 2 NO N ; + 2 H20 may proceed by the following mechanism: 2 NO - N20 (kand k) H + N202 + NO + H2O (kz) H + NO + N2 + H2O (ku). Use the steady-state approximation to predict the rate law for the formation of the product N2.
The body can break down alcohol through the following reaction: ethanol + NAD +→ acetadehyde + NADH + H+ Calculate Delta G* for this reaction at 25C. The standard reduction potentials are: ethanol →acetaldehyde + 2H+ + 2e- E = -0.197V NAD+ + H+ + 2e- → NADH E= -0.320V 1. The body can break down alcohol through the following reaction: ethanol + NAD* acetadehyde + NADH+H* Calculate AGº for this reaction at 25°C. The standard reduction potentials are: ethanol...