Question

Problem 18.45 - Enhanced - with Feedback 12 of 20 Review Constants Periodic Table A 1.0 cm tall object is 70 cm in front of a converging lens that has a 20 cm focal length Part A Calculate the image position Express your answer with the appropriate units. Enter positive value if the image is on the other side from the lens and negative value if the image is on the same side as the object. НА + 2 Value Units Submit RA Part B Calculate the image Express your answer with the appropriate units MA th ? Us

Answer 1

Solution A l cm tall object object is 7 cm in front of a converging lens. Focal length of converging lens is 20cm. Part Bo A Tank is taken Let AB is object having Ich height. Direction of incident ray is positive. Coordinate of object = u=-7 focal length = f = 20 Coordinate of innage = v Using Lens formula - tu u = zo 20 v = taze - ㅗ 20 7-20 20x7 140 -13 20x7 7-20 V - Negative sign shows that V = -10.77 image is on the same side as as the object. Image is 10177cm leftward to the lens. Image position x= -10.77cm

V m= = Part B Magnification formala of lens Height of image Height of object Height of image Iv=-10.77 Height of object Height of 1 cm -10.77 - Height of image Poljeet -10.77 +1 -10.77 u= -7 -7 1 Height of image 7 7 1.54 cm Height of image = 1.54 Image Leight ha = 1.54cm