Question

Problem 19.59 Part A Review I Constants I Periodic Table Calculate the image position Express your answer in centimeters to two significant figures. A converging lens with a focal length of 40 em and a diverging lens with a focal length of-40 cm are 170 cm apart A 1.5-cm-tall object is 60 cm in front of the converging lens ern in front of the second lens Submit Request Answer Part B Calculate the image height Express your answer in centimeters to two significant figures

Answer 1

for converging lens

1/ f = 1/ v - 1/u

1/ 40 = 1/v + 1/ 60

v = 120 cm

magnification,

m1 = v/ u = 120 / 60 = 2

now the above image acts as an object for lens 2

Object distance of which is given by

u' = - ( 170 - 120) = - 50cm

again using lens formula for diverging lens

1/f' = 1/ v' - 1/u'

- 1/ 40 = 1/ v' + 1/ 50

v' = 22.22 cm =========>>> Ans

magnification

m2 = v'/u' = 22.22 / 50 = 0.44

net magnification of system

m = h'/h = m1 m2

h'/ 1.5 = 0.44* 2

h' = 1.33 cm =========>>>> Ans

========

Comment in case any doubt, will reply for sure.. Goodluck