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A converging lens with a focal length of 40 cm and a diverging lens with a...

A converging lens with a focal length of 40 cm and a diverging lens with a focal length of -40 cm are 170 cm apart. A 3.0-cm-tall object is 60 cm in front of the converging lens.

1.) Calculate the image position.

2.) Calculate the image height.

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Answer #1

Using lens formula,

1/q1 = 1/f1 - 1/p1 = 1/40 - 1/60

q1 = 120.48 cm

Object distance, P2 = 170 - 120.48 = 49.52 cm

1/q2 = 1/-40 - 1/49.52

q2 = - 22.13 cm

A) image is at distance of 22.13 cm from diverging lens and (170 - 22.13) = 147.87 Cm from convex lens.

B)

M = (-120.48/60)(22.13/49.52) = -0.90

Height = 0.90 x 3 = - 2.69 cm

Comment in case any doubt please rate my answer......

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