Question

an object rools without slipping down a 2.05m high incline.

what is the moment of inertia of the object starting from rest if it has a final velocity of 5.6m/s? express the moment of inertia as a multiple of MR^2

I/(MR^2)=?

Answer 1

Solution in the uploaded image

Solution M A=2.05m lfinal = 5.6m/s conservation. 1 using energy (p imitiak = (XB) 4 Final مح Mxg xh = 1 Mug ² + t I w² ols 2. R2 High = 1 Hugh + 1 I M(gh - uf) x 2 = I lg I = MR² [gh of J x2 I. MR [ 4.8x205 - look e agi 2 (5.67 I - MR? [0.2 81] I - 0.281 MRZ rit like if you understood the solution!!