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Question 5 (Q3) The cell notation for a voltaic cell with the following redox reaction is:...
Question 14 (4 points) The standard cell notation for the following redox reaction is 2 Cr(s) + 3Fe2+ (aq) → 2 Cr3+ (aq) + 3Fe(s) Fe(s) Fe2+ (aq) | Cr3+ (aq) Cr(s) none of the choices 2 Cr(s) 2 Cr3+ (aq) || 3 Fe2+ (aq) 3 Fe(s) Cr(s) Cr3+ (aq) || Fe2+ (aq) | Fe(s) O3 Fe(s) 3 Fe2+ (aq) | 2 Cr3+ (aq) 2 Cr(s)
Half-reaction Cr3+ (aq) + 3e--Cr(s) Fe2+ (aq) + 2e - Fe(s) Fe3+ (aq) - Fe2+ (5) Sn+ (aq) + 2e - Sn2(aq) E (V) -0.74 -0.440 +0.771 +0.154 1. Calculate the standard cell potential for the voltaic cell based on the reaction below, given the table above: 35nt(s) + 2Cr (s) - 2 C (s) + 3 Sn () ANSWER: 2. Calculate the standard cell potential for the voltaic cell based on the reaction below, Riven the table above 3Feb...
4. Use the table below to provide a redox reaction involving the spontaneous oxidation of Cr (balance your final reaction and provide the Ecell). Half-reaction E (V) Cr3+ (aq) + 3e Cr(s) -0.74 Fe(s) -0.440 Fe3+ (aq) + → Fe2+ (s) +0.771 Sn4+ (aq) + 2e Sn2+ (aq) +0.154 Fe2+ (aq) + 2e-
I need help with questione 1-12 and discussion question 1 and
2. The previous pictures help determine the chart. Please Show Work
thank you so much
An oxidation half-reaction is characterized by electrons appearing on the product side. The oxidation of aluminum for instance would be represented thusly: Al(s) → Al3+ + 3e- (1) An reduction half-reaction is characterized by electrons appearing on the reactant side. The reduction of ferrous iron for instance would be represented thusly: Fe2+ + 2e...
38. The following redox half reactions are combined in a voltaic cell. Which reaction occurs at the cathode and what is the Eceu? Fe2+(aq) + 2e → Fe(s) E°=-0.44 V Cu²+(aq) + 2e → Cu(s) E°= 0.34 V a) b) c) d) Cu2+(aq) + 2e → Cu(s), Ecell = 0.78 V Fe2+(aq) + 2e → Fe(s), Ecel = 0.78 V Fe2+(aq) + 2e → Fe(s), Ecell =-0.10 V Cu²+(aq) + 2e → Cu(s), Ecel = 0.10 V Cu²+ (aq) +...
Table 20.2 Half-reaction E° (V) Cr3+ (aq) + 3e- → Cr (s) -0.74 Fe2+ (aq) + 2e- Fe () -0.440 Fe3+ (aq) + e- → Fe2+ (s) +0.771 Sn4+ (aq) + 2e- Sn2+ (aq) +0.154 The standard cell potential (Eºcell) for the voltaic cell based on the reaction below is V. Cr (s) + 3Fe3+ (aq) + 3Fe2+ (aq) + Cr3+ (aq) A) -1.45 B) +2.99 C) +1.51 D) +3.05 E) +1.57
Table 20.2 Half-reaction E° (V) Cr3+ (aq) + 3e- → Cr(s) -0.74 Fe2+ (aq) + 2e- Fe (5) -0.440 Fe3+ (aq) + e - Fe2+ (s) +0.771 Sn4+ (aq) + 2e- Sn2+ (aq) +0.154 The standard cell potential (Eºcell) for the voltaic cell based on the reaction below is V. 35n4+ (aq) + 2Cr (s) → 2Cr3+ (aq) + 3Sn2+ (aq) A) +1.94 B) +0.89 C) +2.53 D) -0.59 E) -1.02
A voltaic cell contains the following species involved in oxidation and reduction reactions: Au (s), Fe (s), Aut (aq), and Fe2+ (aq). What is the Eº of that cell? Half reaction Ed/V Aut(aq) +e Au(s) 1.692 Fe (aq) + 2e-> Fe(s) -0.447 2.937 V C 1.9155 V C 1.245 V 2.139 V 3.831 V
PART II. Voltaic Cell Design In each of the following two problems, there's a pair of half-reactions shown in standard reduction form. In each problem, reverse the appropriate half-reaction, and indicate the following at the diagrams: a) voltage displayed by voltmeter (assume standard conditions) b) content of solution in each half-cell c) substance used for each electrode d) which electrode is anode, which is cathode e) which electrode is (+), which is (-) f) direction of electron flow g) direction...
Choose the overall chemical reaction that takes place in a voltaic cell represented by the the following cell diagram Cr(s)| Cr3+(aq) || Fe3+(aq), Fe2+(aq) | Pt(s). Cr3+(aq) + 3Fe2+(aq) → Cr(s) + 3Fe3+(aq) O Cr(s) + 3Fe3+(aq) → Cr3+(aq) + 3Fe2+(aq) O Cr(s) + Fe2+(aq) → Cr3+(aq) + Fe3+(aq) Cr(s) + 3Fe2+(aq) → Cr3+(aq) + 3Fe3+(aq) O Cr(s) + 2Fe3+(aq) → Cr3+(aq) + 2Fe2+(aq)