Question

P = 130 KN 12 5 13 P, = 40 kn M = 45 kNm 2m B A 4m 1,5m 1,5m ANTWOORD:

a) Convert the given system to an equivalent force and torque at point A.
Write the powers / moments as cartesian vectors.
b) Determine the point on the as AB where the torque of the equivalent system is 0. Enter the distance from point A.
c) Make a Free Body Scheme and determine the forces in A and B at equilibrium.

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Answer #1

124 Pi: 130kn 13 3 m S m1 = 45 KN.M B 2m P2 = 40KN € 4m Ism 40x 40x12 B RAX mi RBy IRAY Now taking Solution Cities Point A is(a) The equivalent force acting at A is given by RAX 2 + Ray = (36.92 î +115.2s ĝ) KM P2 А B RARY mo Ray mome Torque is zero

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