Question

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An object is located at a distance of 7.00 cm from a thin lens with a radius of curvature of 66.0 mm. The image of the object is inverted. Is the image real or virtual, and how far is the image from the lens? Real, 6.24 cm O Virtual, 6.24 cm Real, 116 cm O Virtual, 116 cm Real, 2.2 cm

Answer 1

from converging cens image is become inverted. Radius of curvature R = 66 mm= 6.6cm for this cent focal length f= 2 = 66 6.6= 3.3cm For converging Cens focal length is positive fathe f=t3.3cm object is left side of eens so from Sign-convention uis Object u=-7cm - -7 x 3.3 6.243 CM/L -7+3.3 tt = v= uf 4+f Timage distance forom lens 2 vis the means right side of lens so image is virtual For concave mirror image is invented means left side of mirror. So v=ove v=-2.5m= - 2 Solm focal length f= R = 100 - For Concare mirror focal length is negative f= -5o mirror formula Itt = = Ź + 1 u= Uf =(-250)-so) f -got so 2 socm v-f u=-62.5cm image distance magnification m=- object distance els m=-(-250) -62.5 =-4 m= -4