Tullula's spaceship is travelling through deep space at a rate of 13.72 m/s. For a period...

Question

Question

Tullulas spaceship is travelling through deep space at a rate of 13.72 m/s. For a period of 2.12 s she accelerates at a rate

Answer 1

Answer #1

Under uniform acceleration,s=ut+1/2a*t^2, where s is displacement, u is initial velocity, t is time and a is acceleration.

Here,u=13.72 m/s, t=2.12 s, a=7.89 m/s2.

So, s=13.72*2.12+1/2*7.89*2.12*2.12=46.81681 m.

Answer 2

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