Question

CULINO Stooping ouurer: simple random sample or ugne college Tres night. The results were were asked how many hours or steep
0 0
Add a comment Improve this question Transcribed image text
Answer #1

Solution, Given that x = 9.75 S = 5.84929788. n = 8 C - 99% = 0.99 At 99% confidence intesvalt is x = - = -0.99 = 0.01 a 0.01

Add a comment
Know the answer?
Add Answer to:
CULINO Stooping ouurer: simple random sample or ugne college Tres night. The results were were asked...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Sleeping outlier: A simple random sample of eight college freshmen were asked how many hours of...

    Sleeping outlier: A simple random sample of eight college freshmen were asked how many hours of sleep they typically got per night. The results were 24 6 8.5 8 8.5 7.5 6.5 9 Send data to Excel Notice that one joker said that he sleeps 24 a day. Part: 0/ 3 Part 1 of 3 (a) The data contain an outlier that is clearly a mistake. Eliminate the outlier, then construct a 90 % confidence interval for the mean amount...

  • Meraw-Hi Connect Math Lower and upper fence celator istatistical Daler Whaththe correlations Question 28 of 44...

    Meraw-Hi Connect Math Lower and upper fence celator istatistical Daler Whaththe correlations Question 28 of 44 (1 point) Attempt 1 of 1 View question in a popup 12h 58m Remaining 72 Saccon Frencie 38 Sleeping outlier: A simple random sample of eight college freshmen were asked how many hours of sleep they typically got per night. The results were dlo 8.5 24 8.5 8 7.5 9 6.5 6 Send data to Excel Notice that one joker said that he sleeps...

  • in a simple random sample of 190 households, the sample mean number of personal computers was...

    in a simple random sample of 190 households, the sample mean number of personal computers was 2.78. assume the population standard deviation is 0.41. a) a 99.8% confidence interval for the mean number of personal computers is ----< mean <----- 2) a simple random sample of eight college freshman were asked about how many hours of sleep they typically got per night. the results were 7.5, 8, 6.5, 24, 8.5, 6.5, 7, 7.5 a) the data contains an outlier that...

  • Based on a random sample of 1140 ​adults, the mean amount of sleep per night is...

    Based on a random sample of 1140 ​adults, the mean amount of sleep per night is 8.56 hours. Assuming the population standard deviation for amount of sleep per night is 1.3 ​hours, construct and interpret a 90​% confidence interval for the mean amount of sleep per night. A 9090​% confidence interval is ​(nothing​,nothing​). ​(Round to two decimal places as​ needed.) Interpret the confidence interval.

  • Based on a random sample of 1040 adults, the mean amount of sleep per night is...

    Based on a random sample of 1040 adults, the mean amount of sleep per night is 8.37 hours. Assuming the population standard deviation for amount of sleep per night is 2.7 hours, construct and interpret a 95% confidence interval for the mean amount of sleep per night. A 95% confidence interval is (DD (Round to two decimal places as needed.)

  • Based on a random sample of 1160 ​adults, the mean amount of sleep per night is...

    Based on a random sample of 1160 ​adults, the mean amount of sleep per night is 8.49 hours. Assuming the population standard deviation for amount of sleep per night is 3.6 ​hours, construct and interpret a 95​% confidence interval for the mean amount of sleep per night. A 95% confidence interval is (_____​,_______). ​(Round to two decimal places as​ needed.)

  • Based on a random sample of 1080 ​adults, the mean amount of sleep per night is...

    Based on a random sample of 1080 ​adults, the mean amount of sleep per night is 8.41 hours. Assuming the population standard deviation for amount of sleep per night is 3.8​hours, construct and interpret a 90​% confidence interval for the mean amount of sleep per night. A 90​% confidence interval is ​(nothing​,nothing​). ​(Round to two decimal places as​ needed.)

  • Based on a random sample of 1180 adults, the mean amount of sleep per night is...

    Based on a random sample of 1180 adults, the mean amount of sleep per night is 7.85 hours. Assuming the population standard deviation for amount of sleep per night is 1.4 hours, construct and interpret a 95% confidence interval for the mean amount of sleep per night. A 95% confidence interval is (DD Round to two decimal places as needed.) Interpret the confidence interval O A. O B. ° C. 0 D. We are 95% confident that the interval actually...

  • 0 Based on a random sample of 1140 adults, the mean amount of sleep per night...

    0 Based on a random sample of 1140 adults, the mean amount of sleep per night is 8.42 hours. Assuming the population standard deviation for amount of sleep per night is 2.9 hours, construct and interpret a 95% confidence interval for the mean amount of sleep per night. A 95% confidence interval is (2.) (Round to two decimal places as needed.) Interpret the confidence interval. O A. We are 95% confident that the interval actually does contain the true value...

  • A random sample of community college students was asked the number of hours they sleep on...

    A random sample of community college students was asked the number of hours they sleep on a typical week-night during a given academic term. The sample data are as follows: 8 6 4 5 3 7 S 4 3 4 4 5 6 8 7 7 7 3 3 4 What is the 90% confidence interval estimate for the true mean amount of sleep time per night spent by community college students during a academic term? a) The data give...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT