Question

Question I need answered is bold faced here: Relativistic Mass Still standing in the same spaceship... With respect to an observer in a given frame of reference, how fast would the spaceship have to move in order for your [moving] mass to be double your resting mass? From your perspective, what will be your mass on board the spaceship? In the last two weeks we have investigated time, length, and mass at very high velocities. Identify the unifying physical principle that ties all three of these investigations together and explain how they are connected. Use the following equation for relativistic mass to solve this problem. Make sure to show how you arrived at your answers. If you need assistance or have any questions please post in the Course Questions Help Forum on the course homepage. Equation for relativistic mass: Where: m = the relative mass of a moving object m' = the mass of the object at rest v = the velocity of the object c = the speed of light

Below screenshot shows the original equation.( along with the problems that need to get solved.)

M Inbox m Course x = Final Prx Sample x m SOS_20 x E Space X B Space х = Length х C Get Hox My Drix Gwas is х + c docs.google.com/document/d/1t5tBe24G4df1RFm876m-kosMtcVb_cXUPju4t1KxLmQ/pub * Apps • FHS Library P PowSch G Sch email in AMNH grad-course... NA textbook-One Univ... EFHS Behavioral Rep... The HiSET Exam BL BLessons MUDL Cohort 3 Other bookmarks Length Contraction and Relativistic Mass Updated automatically every 5 minutes Relativistic Mass Still standing in the same spaceship... 1. With respect to an observer in a given frame of reference, how fast would the spaceship have to move in order for your [moving] mass to be double your resting mass? 2. From your perspective, what will be your mass on board the spaceship? 3. In the last two weeks we have investigated time, length, and mass at very high velocities. Identify the unifying physical principle that ties all three of these investigations together and explain how they are connected. Use the following equation for relativistic mass to solve this problem. Make sure to show how you arrived at your answers. If you need assistance or have any questions please post in the Course Questions Help Forum on the course homepage. Equation for relativistic mass: m=m'/V1–02/c2 Where: m = the relative mass of a moving object m' = the mass of the object at rest v = the velocity of the object c = the speed of light Activate Windows Go to Settings to activate Windows. Published by Google Drive - Report Abuse Type here to search PS 5:22 PM 7/30/2020

Below is the first part of the problems that has already been solved:

SPACE, TIME AND MOTION Length Contraction and Relativistic Mass Length Contraction Let's continue to investigate your space vacation from last week. Your spaceship, which has a proper length of 300 m, passes near a space platform while you are moving at a relative speed of 0.86 c. What is the length of the spaceship when measured by someone on the space platform? What is the length of the spaceship from your perspective in the spaceship? The length is, of course, different from these two frames of reference. Does the length really change? Use the following equation for length contraction to solve the problems above. Make sure to show how you arrived at your answers. If you need assistance or have any questions please post in the Course Questions Help Forum on the course homepage. Equation for length contraction Where: L = The length of the spaceship as seen by the observer L' = The proper length of the spaceship v = The velocity of the spaceship c = The speed of light.

Answer 1

Plugging the condition onto the given equation:

$2{m}'=\frac{{m}'}{\sqrt{1-\frac{v^{2}}{c^{2}}}}$

$\sqrt{1-\frac{v^{2}}{c^{2}}}=\frac{1}{2}$

$1-\frac{v^{2}}{c^{2}}=\frac{1}{4}$

$\frac{v^{2}}{c^{2}}=\frac{3}{4}$

$v^{2}=\frac{3}{4}c^{2}$

$v=0.866c$