Question

So this is the question I asked and this is the answer I got. I still have a few doubts over the questions and would like clarification.An engineering system of a moving object is represented by the second order differential equation as shown in Eqn. Q2: y(t)Given y(t) + 4 y(t) = -5 ylo) = 20 ; y(0)=0 L [yCt) + 4 y(t)] = [(-5) 2(y) + 4 Lly) = -52(1) =) SQ LIG) - syco) ylco) + 4

Three things I want clarification on:

1) What are the assumptions made in part a and part b
2) A step by step clarification of the solving process of the answer above

3) A solution to part B and an explanation on what is the damping coefficient and what the comparison of the answers would mean.

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Answer #1

- Assumptions for Part 2! Assuming is It max. Spring System Spring is mass less. medius, aroundlody 2 NO ViS COUS force sprinGiven, Y (4) + 4414) -a. equivalent System: sa + ku: cit FIAI toas e damping coefficient ks Spring constant. FIHz- 5 for parHere , في with initial conclitions . to) کل رها او { ۱۶) ) ده - (St۶۰ - (275 م initial condition. مرد b (4) - فر (5) مر{ -،Note: { \: 1 - 9 : Cos at ş * รุ่น : นาง ๆ ₂ Sinat S 249 5 ไnt (2 +) { to Rio (1+) - S พ 3 (4) - u this indicates it is Sinus? taking ६ : 0.5 85 ca &2 km en ron c= 10.5) (2) Siu 1 damping coefficient. Generally; C. c. sich fo= Damping force, it acts[s. ۹۲) - روہی (ranha cons] - conh ۔ - (ا .2 ! تزی و ئے (s) + . + - ) 11 ): -کر 50 زبا+د+خیی By partial fraction, و دو ) = دسNote: qi a(5116) ethe, costist) (St} + illa are preparate - the. sin I VIS +) (S+ 2)² + 4 41H) = t et/2 (cios PI52)) + )) tst bi Hy lovis é Cos visit sinl STS) + Y+) sh alt sa ē 42 YiH. - slut 0 0 time increases. die eventually The oscillations wil

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