Question

(1 point) An animation has two scenes, each of them being one second long. In the first scene, an object moves along the path Pi(t) = (8t2 – 9t, – 10t² + 4, 8t2 + 3t + 10) for 0 <t< 1. At the end of the scene, the object's acceleration immediately becomes zero, and remains zero throughout the second scene. The vector-valued function P2 (t) for the object's path in the second scene also uses 0 St51, so that t = 0 in the second scene is the same moment as t = 1 in the first scene. What is P2 (t)? Answer: P2(t) =(

Answer 1

Solo PI(t) = (8t2-gt, -10t2 tu, 84 +36 +10) Pict) = (16t-9, -2ot , 16t+3) P,'() = (16-9, -20 , 16+3) = (1, -20, 19) acceleration constant for relocity o velocity should be - P2 (t) = (+,-20, 19) 2 P2 (t) = S(1, -20, 19) at (= (Yttc,, -20t+(2, rgt+ (3) We have. P200) = PICI) = (8-9, -10+4, 8+3+10) P2 (0) = (-1,-6, 21) i Corci, 0+(2, 0+ (g) = (-1, -6, 21) CI=-1, (2=-6, (3=21 So, P2(t) = (4t-1, -20t - 6, 196+21)

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