Solution:
Givendata:
In analyzing hits by B bombers Targets are subdivided to 465 regions each an area of .02 km2.
Given,
p = 1/465
sample n = 411
Mean = np
= 411/465
= 0.8839
Standard deviation = sqrt(npq) = sqrt(411*1/465(1- 1/465)) = 0.9391
a)
X = 2
z = (x - u)/s
substitute values
= (2 - 0.8839)/0.9391
= 1.1885
P(z < = 1.1885) = 0.8826818 [since from z table]
= 0.8827
b)
X = 3
P(z < (3 - 0.8839)/0.9391) = P(z < 2.25)
= 0.9877755 [since from z table]
= 0.9878
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In analyzing hits by B bombers Targets are subdivided to 465 regions each an area of...
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