Question

The beam shown is subjected to a shear of V = 14 kip. The area moment of inertia of the beam's cross section about its neutral axis is 56 in⁴. Determine following: 

(a) Shear stress at point A if it is located in the flange, 

(b) Shear stress at point A if it is located in the web, and 

(c) The maximum shear stress acting on the beam cross section.

Answer 1

INAE 56 in. Given that manimom shear fora in the Cooss section Seman = lu kip -> Anea moment of inertia about N.A is u in K 키 K lin (LAW HAR 6 in Yence 5 klin Tessin inID I in -) (LA). -> on frange CA) (BA) & uin (SFA)(QA) (INA) (BAP in frange Port to QA - (CI)(3-0.5) = 10 in 3. CEA) (14X103) Co) (56) (4) 625 psi

CAP = 625 Psi YA) - on Web = ESTA) (QA) GENA) (baw (BA) walin +24x103x10 (56) (1) CLAW CA) w 2500 Psi > on web. Pontion Eman -> on Neutral auch anis eman ENJA (SPA) (QNA) (INA) (INA) QNIA (WC) (2.5)+(2) (1) (2/2). (b)NA = lin QUIA = Qmax N 12 in 3 Lman = (lukio 3) (12) (560) e 3000 psi aman = 3000 Psi poi)

In the question a and b the value of width of c/s area changes only.

Answer 2

INAE 56 in. Given that manimom shear fora in the Cooss section Seman = lu kip -> Anea moment of inertia about N.A is u in K 키 K lin (LAW HAR 6 in Yence 5 klin Tessin inID I in -) (LA). -> on frange CA) (BA) & uin (SFA)(QA) (INA) (BAP in frange Port to QA - (CI)(3-0.5) = 10 in 3. CEA) (14X103) Co) (56) (4) 625 psi

CAP = 625 Psi YA) - on Web = ESTA) (QA) GENA) (baw (BA) walin +24x103x10 (56) (1) CLAW CA) w 2500 Psi > on web. Pontion Eman -> on Neutral auch anis eman ENJA (SPA) (QNA) (INA) (INA) QNIA (WC) (2.5)+(2) (1) (2/2). (b)NA = lin QUIA = Qmax N 12 in 3 Lman = (lukio 3) (12) (560) e 3000 psi aman = 3000 Psi poi)

Answer 3

lin shear force lin lin 3 in lin A web 12 Nientral casus z momest of Inertia about neutral acis iš I56 inh ..() Maximum shear stress acha axis Giveni Crossection of beam v=14 Kip bin ini 2) a) shear stress at points if itsis loaded in flange Vx(A3) z? Taz 14x C4X1X2.5) 2) ITA= 625psi as shear 56 x 4 lange stress at flanger b) shear stress cat point a if load in web 2) Ta 14x cexlx 2.5) = TA: 2.5ksi = 2500 564 U in the beam as shear stress at Neutral Imaxe vx(AG) I b 2) "A I b 22 web lux [Ux1X 2.5) + (2x1x1)] 56x I > Tmax = 3ksi = 3000 psi I Mascimum shear stress developed cet Neutral axis

Answer 4

Answer 5

INAE 56 in. Given that manimom shear fora in the Cooss section Seman = lu kip -> Anea moment of inertia about N.A is u in K 키 K lin (LAW HAR 6 in Yence 5 klin Tessin inID I in -) (LA). -> on frange CA) (BA) & uin (SFA)(QA) (INA) (BAP in frange Port to QA - (CI)(3-0.5) = 10 in 3. CEA) (14X103) Co) (56) (4) 625 psi

CAP = 625 Psi YA) - on Web = ESTA) (QA) GENA) (baw (BA) walin +24x103x10 (56) (1) CLAW CA) w 2500 Psi > on web. Pontion Eman -> on Neutral auch anis eman ENJA (SPA) (QNA) (INA) (INA) QNIA (WC) (2.5)+(2) (1) (2/2). (b)NA = lin QUIA = Qmax N 12 in 3 Lman = (lukio 3) (12) (560) e 3000 psi aman = 3000 Psi poi)