Question

According to Masterfoods, the company that manufactures M&M's, 12% of peanut M&M's are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. You randomly select five peanut M&M's from an extra-large bag of the candies. (Round all probabilities below to four decimal places; 1.e. your answer should look like 0.1234, not 0.1234444 or 12.34%.) Compute the probability that exactly two of the five M&M's are yellow. Compute the probability that two or three of the five M&M's are yellow. Compute the probability that at most two of the five M&M's are yellow. Compute the probability that at least two of the five MaM's are yellow.

Answer 1

solution: plyellow) o.15 roda m-x na Xn Bimonial P(x) = (2) p*qm-x 2 3. a) P(x=2) 0.1382 (5) (0.15) 10.85) b) P(x=2003) (2 3 2 --(s) + 3 2 Plx=2) + P(x=3) ( 1) (0.15)10.85) + ( 1760.15)10.65) a 0.1626 c) P/X&2) P(x=0) + PIX=)) + f(x=2) 2 X (0.15 (0.85) x=0 12F 0.9734 5-X Х d) ? (X2) I' 13) (0-15) 60-85) 19 X=2 0.1648 28.