Probability of brown candies = 0.10
Probability of red candies = 0.10
Probability of yellow candies = 0.20
Probability of blue candies = 0.20
Probability of orange candies = 0.20
Probability of green candies =1-0.10-0.10-0.20-0.20-0.20 = 0.20
a) Probability of all blue candies, P(Blue) = (0.20)4 = 0.0016
b) Probability that none is green, P(None green) = (0.80)4 = 0.4096
c) Probability of at least one red, P(at least one red) = 1 - P(No red)
= 1 - (0.90)4 = 1 - 0.6561 = 0.3439
d) Probability that the fourth one is the first one that is brown = P(not brown)*P(not brown)*P(not brown)*P(brown)
= 0.90*0.90*0.90*0.10 = 0.0729
The masterfoods company manufactures bags of peanut butter M&Ms. they report that they make 10% each...
According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. (Round your answers to 4 decimal places where possible) a. Compute the probability that a randomly selected peanut M&M is not brown. b. Compute the probability that a randomly selected peanut M&M is yellow or green. c. Compute the probability that two randomly selected peanut M&M’s are both yellow. d....
According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. (Round your answers to 4 decimal places where possible) a. Compute the probability that a randomly selected peanut M&M is not green. b. Compute the probability that a randomly selected peanut M&M is blue or green. c. Compute the probability that two randomly selected peanut M&M’s are both yellow. d....
According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. You randomly select five peanut M&M’s from an extra-large bag of the candies. (Round all probabilities below to four decimal places; i.e. your answer should look like 0.1234, not 0.1234444 or 12.34%.) Compute the probability that exactly two of the five M&M’s are yellow. Compute the probability that two...
According to Masterfoods, the company that manufactures M&M's, 12% of peanut M&M's are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. You randomly select five peanut M&M's from an extra-large bag of the candies. (Round all probabilities below to four decimal places; 1.e. your answer should look like 0.1234, not 0.1234444 or 12.34%.) Compute the probability that exactly two of the five M&M's are yellow. Compute the probability that two or...
2. According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. You randomly select six peanut M&M’s from an extra-large bag of the candies. (Round all probabilities below to four decimal places; i.e. your answer should look like 0.1234, not 0.1234444 or 12.34%.) a.) Compute the probability that exactly two of the six M&M’s are yellow. b.) Compute the probability...
According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. You randomly select six peanut M&M’s from an extra-large bag of the candies. (Round all probabilities below to four decimal places; i.e. your answer should look like 0.1234, not 0.1234444 or 12.34%.) Compute the probability that exactly five of the six M&M’s are red Compute the probability that four or...
According to Masterfoods, the company that manufactures M&M's, 12% of peanut M&M's are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. You randomly select four peanut M&M's from an extra-large bag of the candies. (Round all probabilities below to four decimal places; i.e. your answer should look like 0.1234, not 0.1234444 or 12.34%.) Compute the probability that exactly three of the four M&M's are yellow. P(x = 3) Compute the probability...
According to Masterfoods, the company that manufactures
M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12%
are red, 23% are blue, 23% are orange and 15% are green. You
randomly select five peanut M&M’s from an extra-large bag of
the candies. (Round all probabilities below to four decimal places;
i.e. your answer should look like 0.1234, not 0.1234444 or
12.34%.)
Compute the probability that exactly two of the five M&M’s
are yellow.
Compute the probability that two or...
According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. You randomly select peanut M&M’s from an extra-large bag looking for a blue candy. (Round all probabilities below to four decimal places; i.e. your answer should look like 0.1234, not 0.1234444 or 12.34%.) Compute the probability that the first blue candy is the eighth M&M selected. Compute the probability that...
39. M&M's The Mars company says that before the intro- duction of purple, yellow candies made up 20% of their plain M&M's, red another 20%, and orange, blue, and green each made up 10%. The rest were brown. a) If you pick an M&M at random, what is the probabil- ity that 1. it is brown? 2. it is yellow or orange? 3. it is not green? 4. it is striped? b) If you pick three M&M's in a row,...