According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. You randomly select five peanut M&M’s from an extra-large bag of the candies. (Round all probabilities below to four decimal places; i.e. your answer should look like 0.1234, not 0.1234444 or 12.34%.)
Compute the probability that exactly two of the five M&M’s
are yellow.
Compute the probability that two or three of the five M&M’s
are yellow.
Compute the probability that at most two of the five M&M’s
are yellow.
Compute the probability that at least two of the five M&M’s
are yellow.
If you repeatedly select random samples of five peanut
M&M’s, on average how many do you expect to be yellow? (Round
your answer to two decimal places.) yellow M&M’s
With what standard deviation? (Round your answer to two decimal
places.) yellow M&M’s
1)
probability that exactly two of the five M&M’s are yellow :
probability = | P(X=2)= | (nCx)px(1−p)(n-x) = | 0.1382 |
2)
probability that two or three of the five M&M’s are yellow :
probability = | P(2<=X<=3)= | ∑x=x1x2 (nCx)px(1−p)(n-x) = | 0.1626 |
3)
probability that at most two of the five M&M’s are yellow :
probability = | P(X<=2)= | ∑x=0x (nCx)px(1−p)(n-x) = | 0.9734 |
4)
probability = | P(X>=2)= | 1-P(X<=1)= | 1-∑x=0x-1 (nCx)px(1−p)(n-x) = | 0.1648 |
5)
expect to be yellow =np=0.75
6)
standard deviation σ=√(np(1-p))= | 0.80 |
According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s are brown, 15% are...
According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. You randomly select five peanut M&M’s from an extra-large bag of the candies. (Round all probabilities below to four decimal places; i.e. your answer should look like 0.1234, not 0.1234444 or 12.34%.) Compute the probability that exactly two of the five M&M’s are yellow. Compute the probability that two...
According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. You randomly select six peanut M&M’s from an extra-large bag of the candies. (Round all probabilities below to four decimal places; i.e. your answer should look like 0.1234, not 0.1234444 or 12.34%.) Compute the probability that exactly five of the six M&M’s are red Compute the probability that four or...
2. According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. You randomly select six peanut M&M’s from an extra-large bag of the candies. (Round all probabilities below to four decimal places; i.e. your answer should look like 0.1234, not 0.1234444 or 12.34%.) a.) Compute the probability that exactly two of the six M&M’s are yellow. b.) Compute the probability...
According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. You randomly select peanut M&M’s from an extra-large bag looking for a blue candy. (Round all probabilities below to four decimal places; i.e. your answer should look like 0.1234, not 0.1234444 or 12.34%.) Compute the probability that the first blue candy is the eighth M&M selected. Compute the probability that...
According to Masterfoods, the company that manufactures M&M's, 12% of peanut M&M's are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. You randomly select five peanut M&M's from an extra-large bag of the candies. (Round all probabilities below to four decimal places; 1.e. your answer should look like 0.1234, not 0.1234444 or 12.34%.) Compute the probability that exactly two of the five M&M's are yellow. Compute the probability that two or...
According to Masterfoods, the company that manufactures M&M's, 12% of peanut M&M's are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. You randomly select four peanut M&M's from an extra-large bag of the candies. (Round all probabilities below to four decimal places; i.e. your answer should look like 0.1234, not 0.1234444 or 12.34%.) Compute the probability that exactly three of the four M&M's are yellow. P(x = 3) Compute the probability...
According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. (Round your answers to 4 decimal places where possible) a. Compute the probability that a randomly selected peanut M&M is not brown. b. Compute the probability that a randomly selected peanut M&M is yellow or green. c. Compute the probability that two randomly selected peanut M&M’s are both yellow. d....
According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. (Round your answers to 4 decimal places where possible) a. Compute the probability that a randomly selected peanut M&M is not green. b. Compute the probability that a randomly selected peanut M&M is blue or green. c. Compute the probability that two randomly selected peanut M&M’s are both yellow. d....
The masterfoods company manufactures bags of peanut butter M&Ms. they report that they make 10% each brown and red candies, and 20% each yellow, blue, and orange candies. The rest of the candies are green. If you pick four M&Ms in a row, what is the probability that they are: A all blue? B none are green? C at least one is red? D the fourth one is the first one that is brown?
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