Question

An object has an initial negative velocity of your last digit of the university ID +1) m/s . If it has a positive acceleration of 0.075 m/s2, how will velocity be immediately affected? Select one: a. Velocity will decrease b. Velocity will either increase or decrease ocity will increase OC. O d. Velocity will be constant TAS

3+1 = negative accelaration

Answer 1

Acceleration=change in velocity/time

given acceleration a=.075 m/s

initial point velocity V₁= -4 m/s

final velocity is V₂

a=(V₂-V₁)/t

.075=(V₂+4)/t

V₂=.075*t-4

here V₂ value is depends on t so time is always in positive value and for all possible values of t=1,2,3,4,5,...etc

V₂ will be more than -4 m/s

(it is simply a equation in which some positive value is added in -4,hence value will be increased, -3.5 is more than -4)

SO velocity will increase.

OPTION C IS CORRECT.