Given the following equation, how many grams of Li are needed to produce 10.0 g of H2?
2Li(s) + 2H2O(l) ⟶⟶ 2LiOH(aq) + H2(g)
Molar Masses:
Li = 6.94 g/mol
H2O = 18.02 g/mol
LiOH = 23.95 g/mol
H2 = 2.02 g/mol
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