Question

How many grams of carbon dioxide would be required to react with 10.0 g of LIOH in the following chemical reaction? 2 LIOH(s) +CO2 (g)- Li COs (s)+HO (I)

Answer 1

Molar mass of LiOH,
MM = 1*MM(Li) + 1*MM(O) + 1*MM(H)
= 1*6.968 + 1*16.0 + 1*1.008
= 23.976 g/mol

mass of LiOH = 10 g
mol of LiOH = (mass)/(molar mass)
= 10/23.98
= 0.4171 mol

According to balanced equation
mol of CO2 reacted = (1/2)* moles of LiOH
= (1/2)*0.4171
= 0.2085 mol


Molar mass of CO2,
MM = 1*MM(C) + 2*MM(O)
= 1*12.01 + 2*16.0
= 44.01 g/mol


mass of CO2 = number of mol * molar mass
= 0.2085*44.01
= 9.178 g
Answer: 9.18 g