I dont understand what the procedure would be to figure this out.
is M the weight of the glider or a variable that needs to be solved
for? to find g do I just use the equation for a and solve for g?
how does time from the photogates play a part in my data?Homework Answers
Yes, M is the mass of the glider which is moving on the table ( probably between the photo gates). The value of M and m should be known to you before doing the experiment.
The ultimate aim of the procedure is to find the value of 'g' which will be the slope of m / M + m VS a graph.
Now, To find acceleration, a , we need to use photo gates.
Measure the initial height of hanging mass from the ground and record it. Now let the system move under influence of gravity. record the time taken by the hanging mass to just hit the ground.
now, we can find acceleration using kinematics
h = 1/2at2
a = 2h / t2
you recorded the height, and now you have got the time..........so, you can easily find a.
repeat this same procedure for at least 5 times and make the graph
then deduce the value of 'g' from the graph.
Add Answer to:
I dont understand what the procedure would be to figure this out.
is M the weight...
I need help for numbers 1 and 3. For number one I measured the height of...
I need help for numbers 1 and 3. For number one I
measured the height of the track at angle. One of the heights was
.082m. hypotenuse 1.013m. I did sin^-1(.082/1.013) and got 4.64
degrees. I used a sensor and aquired data for change in v and t as
a glider fell down the track. I calculated the acceleration at that
height and angle as -10.18 m/s^2. final V was 1.48, initial V .687.
final t=.0675, initial t= .1454.
For...
I’m slightly off for part A and I dont understand what part B is asking me. Beyond confused,
I’m slightly off for part A and I dont understand what part B is
asking me. Beyond confused,
REMARKS The moment of inertia is smaller in part (B) because in this configuration the 0.20-kg spheres are essentially located on the axis of rotation. QUESTION If one of the rods is lengthened, which one would cause the larger change in the moment of inertia? the rod connecting balls two and four the rod connecting the bars one and three PRACTICE IT...
I HAVE the answer (B) but i dont know how to get it, please explain. my professor wrote down a bunch of equations but i dont understand them, please explain in words as if i were stupid. i have atta...
I HAVE the answer (B) but i dont know how to get it, please
explain. my professor wrote down a bunch of equations but i dont
understand them, please explain in words as if i were stupid.
i have attached the sheet of notes he wrote on this problem to
make your life much easier, you dont really have to solve anything,
as the answers are right here, all you have to do is literally
explain to me how these...
I dont have excel please help! It's asking to calculate the acceleration, then calculate the mhg,...
I dont have excel please help! It's asking
to calculate the acceleration, then calculate the mhg,
then graph them, and report the slope. The slope is the mass of
Bob.
A group of students, performing the same "Uniform Circular Motion" experiment that you performed in lab, obtained the following results. r(m) mn (kg) t(s) 0.1825 0.06625 172.57 0.2430 0.0965 169.38| 0.2610 0.1055 71.27 0.2980 0.124 170.28 0.3425 0.14625 |71.91 For this table, r is the distance from the center of...
I cannot figure out the uncertainties or how to find amplitude of the velocity. 10.5 A...
I cannot figure out the uncertainties or how to find amplitude of
the velocity.
10.5 A series of weights are hung from a spring and the distances the spring stretches from equilibrium are measured. These data are recorded in the table below. A) Plot the force vs. displacement. B) Calculate the spring constant. (Remember: The spring constant is the slope of the force vs. displacement plot.) 2) Let the spring in the first problem have a mass of(191.3 + or...
Data Trial 1 Trial 2 Trial 3 Distance travelled by mass, S (m) [Same for each trial) 05 m 0.5 m 0...
Data Trial 1 Trial 2 Trial 3 Distance travelled by mass, S (m) [Same for each trial) 05 m 0.5 m 0.5 m Total mass moved (M+m) (KG) 03284 .?'to. same in all trials Hanging mass (m) [different in each trial] Time between gates, t (sec) 14 It% |t2-O-68 t3 #0.99 d Experimental Acceleration, dexp (m/s) (use: S vot t ^at2) 4 165 mls try to make vo Theoretical Acceleration, athe (m/s2) (use: aINM+m Difference (%) mg 15.3 Task 1:...
All questions added because it is needed for Question 6 to 11 to be answered (I believe). Answer Question 6 to 11. Ple...
All questions added because it is needed for Question 6 to 11 to
be answered (I believe).
Answer Question 6 to 11. Please. Thank you
Practical 3: Rotation due to an External Moment - Pre-Lab Preparation Rotation due to an External Moment: Pre-lab Preparation In this practical exercise you will investigate the angular acceleration of a disc about its centre of mass due to an applied moment, and determine the moment of inertia of the disc. Write down the equation...
dont know what im doing wrong Suppose a 28.4-kg child sits 0.67 m to the left...
dont know what im doing wrong
Suppose a 28.4-kg child sits 0.67 m to the left of center on the same seesaw as the problem you just solved in the PRACTICE IT section. A second child sits at the end on the opposite side, and the system is balanced. (a) Find the mass of the second child. 8.55 kg (b) Find the normal force acting at the pivot point. 362 Your answers to part (a) and (b) are not consistent....
the question is in last picture. i provided the lab content... I need guidance. thank you....
the question is in last picture. i provided the lab content...
I need guidance. thank you.
INVESTIGATION 10 ROTATIONAL MOTION OBJECTIVE To determine the moment of inertia I of a heavy composite disk by plotting measured values of torque versus angular acceleration. THEORY Newton's second law states that for translational motion (motion in a straight line) an unbalanced force on an object results in an acceleration which is proportional to the mass of the object. This means that the heavier...
1. In a classical Atwood's machine setup (like this lab), what are the forces that will...
1. In a classical Atwood's machine setup (like this lab), what
are the forces that will be discussed?
a)The weight of the masses on each pulley and the tension in
the string
b)
The weight of the masses on each pulley.
c)
The
Mtotal times g and the tension on the string.
d)
The masses on each pulley and the tension in the string
2. What's the total mass of the system in our case of the
Atwood's machine?
a)...
I need help for numbers 1 and 3. For number one I
measured the height of the track at angle. One of the heights was
.082m. hypotenuse 1.013m. I did sin^-1(.082/1.013) and got 4.64
degrees. I used a sensor and aquired data for change in v and t as
a glider fell down the track. I calculated the acceleration at that
height and angle as -10.18 m/s^2. final V was 1.48, initial V .687.
final t=.0675, initial t= .1454.
For...
I’m slightly off for part A and I dont understand what part B is
asking me. Beyond confused,
REMARKS The moment of inertia is smaller in part (B) because in this configuration the 0.20-kg spheres are essentially located on the axis of rotation. QUESTION If one of the rods is lengthened, which one would cause the larger change in the moment of inertia? the rod connecting balls two and four the rod connecting the bars one and three PRACTICE IT...
I HAVE the answer (B) but i dont know how to get it, please
explain. my professor wrote down a bunch of equations but i dont
understand them, please explain in words as if i were stupid.
i have attached the sheet of notes he wrote on this problem to
make your life much easier, you dont really have to solve anything,
as the answers are right here, all you have to do is literally
explain to me how these...
I dont have excel please help! It's asking
to calculate the acceleration, then calculate the mhg,
then graph them, and report the slope. The slope is the mass of
Bob.
A group of students, performing the same "Uniform Circular Motion" experiment that you performed in lab, obtained the following results. r(m) mn (kg) t(s) 0.1825 0.06625 172.57 0.2430 0.0965 169.38| 0.2610 0.1055 71.27 0.2980 0.124 170.28 0.3425 0.14625 |71.91 For this table, r is the distance from the center of...
I cannot figure out the uncertainties or how to find amplitude of
the velocity.
10.5 A series of weights are hung from a spring and the distances the spring stretches from equilibrium are measured. These data are recorded in the table below. A) Plot the force vs. displacement. B) Calculate the spring constant. (Remember: The spring constant is the slope of the force vs. displacement plot.) 2) Let the spring in the first problem have a mass of(191.3 + or...
Data Trial 1 Trial 2 Trial 3 Distance travelled by mass, S (m) [Same for each trial) 05 m 0.5 m 0.5 m Total mass moved (M+m) (KG) 03284 .?'to. same in all trials Hanging mass (m) [different in each trial] Time between gates, t (sec) 14 It% |t2-O-68 t3 #0.99 d Experimental Acceleration, dexp (m/s) (use: S vot t ^at2) 4 165 mls try to make vo Theoretical Acceleration, athe (m/s2) (use: aINM+m Difference (%) mg 15.3 Task 1:...
All questions added because it is needed for Question 6 to 11 to
be answered (I believe).
Answer Question 6 to 11. Please. Thank you
Practical 3: Rotation due to an External Moment - Pre-Lab Preparation Rotation due to an External Moment: Pre-lab Preparation In this practical exercise you will investigate the angular acceleration of a disc about its centre of mass due to an applied moment, and determine the moment of inertia of the disc. Write down the equation...
dont know what im doing wrong
Suppose a 28.4-kg child sits 0.67 m to the left of center on the same seesaw as the problem you just solved in the PRACTICE IT section. A second child sits at the end on the opposite side, and the system is balanced. (a) Find the mass of the second child. 8.55 kg (b) Find the normal force acting at the pivot point. 362 Your answers to part (a) and (b) are not consistent....
the question is in last picture. i provided the lab content...
I need guidance. thank you.
INVESTIGATION 10 ROTATIONAL MOTION OBJECTIVE To determine the moment of inertia I of a heavy composite disk by plotting measured values of torque versus angular acceleration. THEORY Newton's second law states that for translational motion (motion in a straight line) an unbalanced force on an object results in an acceleration which is proportional to the mass of the object. This means that the heavier...
1. In a classical Atwood's machine setup (like this lab), what
are the forces that will be discussed?
a)The weight of the masses on each pulley and the tension in
the string
b)
The weight of the masses on each pulley.
c)
The
Mtotal times g and the tension on the string.
d)
The masses on each pulley and the tension in the string
2. What's the total mass of the system in our case of the
Atwood's machine?
a)...
Most questions answered within 3 hours.
-
A regression equation that describes the relationship between
the amount of the bill ($) at a...
asked 38 minutes ago -
exercise on VSEPR and molecular structrue.
octahedral
SeCl62-
TeCl62-
ClF62-
distorted
SeF62–
IF6–
asked 1 hour ago -
284 mL of a 0.52 M potassium hydroxide solution is added to 467
mL of a...
asked 1 hour ago -
Little’s Law: Val d’Costa is a world famous ski village in the
French Alps. Because of...
asked 2 hours ago -
Find the absolute error D for the calculation if A + B/C=D A=
9.4 +/- 0.4...
asked 2 hours ago -
New Air Heating and Cooling, manufactures furnaces and central
air units. The company pride itself on...
asked 2 hours ago -
A coach uses a new technique to train gymnasts. Seven
gymnasts were randomly selected and their...
asked 4 hours ago -
While rotating the tires on your car you notice a rock [mass =
0.1 Kg] stuck...
asked 6 hours ago -
Using MARS simulator, write MIPS programs according to
the following scenarios: Receive a positive integer number...
asked 8 hours ago -
An object in front of a concave mirror has a real image that is
11.5 cm...
asked 8 hours ago -
Consider the reaction, C3 H8 + O2 --> CO2 + H2O. How many
moles of O2...
asked 10 hours ago -
You and your opponent both roll a fair die. If you both roll the
same number,...
asked 10 hours ago